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Drupady [299]
3 years ago
8

Given that a varied inversely as b, and b varies directly as the square of c, and a=1 when c=3 find the value of a when c=1/3

Mathematics
1 answer:
ale4655 [162]3 years ago
6 0

Answer:

81

Step-by-step explanation:

When two variables have direct variation, as one variable increases the other variable increases or as one variable decrease, the other decrease. While for an inverse variation, as one variable increase, the other variable decrease or as one variable decrease, the other variable increase.

Given that a ∝ 1/b. Also b ∝ c².

Hence if k is the constant of proportionality, we have:

a ∝ 1 / c²

a = k / c²

When a = 1, c = 3, hence:

1 = k / 3²

k = 1 * 3²

k = 9

Therefore:

a = 9 / c²

When c = 1/3

a = 9 / (1/3)²

a = 9 / (1² / 3²)

a = 9 / (1 / 9)

a = 9 * 9

a  = 81

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Read 2 more answers
Solve for m 1/C+1/m=1/z
9966 [12]
Answer:  " m = zC / (C − z) " .
___________________________________
Explanation:
_________________________
Given:  1/C + 1/m = 1/z ;  Solve for "m".

Subtract  "1/C" from each side of the equation:
____________________________________
1/C + 1/m − 1/C = 1/z − 1/C  ;

to get:  1/m = 1/z − 1/C ;
____________________________________
Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
_________________

mzC {1/m = 1/z − 1/C} ;

to get:  zC = mC − mz ;

Factor out an "m" on the "right-hand side" of the equation:

zC = m(C − z) ;  Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;

zC / (C − z) = m(C − z) / m ;  to get:   24/8 = 3  24

zC/ (C − z) = m ;   ↔   m = zC/ (C − z) .
___________________________________________________
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