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kap26 [50]
3 years ago
6

4. Find the circumference of the circ All changes saved

Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

A. 62.8 in.

Step-by-step explanation:

Circumference of a circle = πd

Diameter (d) = 20 in.

Substitute

Circumference = π × 20

Circumference = 62.8318531

Circumference = 62.8 in. (Approximated to nearest tenth)

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5.<br> Which picture shows a rotation of the flag?<br> (1)<br> (2)<br> (3)<br> (4)
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Answer:

4 my good sir

Step-by-step explanation:

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3 years ago
The triangles below are congruent and their corresponding parts are marked.
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Answer:

The answer is below.

Step-by-step explanation:

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3 years ago
Write the expression as a square of a binomial: 49x^2+12xy+64y^2
DiKsa [7]
STEP
1
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Equation at the end of step 1

((49 • (x2)) + 12xy) + 26y2
STEP
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Equation at the end of step
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(72x2 + 12xy) + 26y2
STEP
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Trying to factor a multi variable polynomial

3.1 Factoring 49x2 + 12xy + 64y2

Try to factor this multi-variable trinomial using trial and error

Factorization fails

Final result :
49x2 + 12xy + 64y2
5 0
3 years ago
The parallel boxplots below display the quiz grades (out of 30) for two of Mrs. Smith’s statistics classes.
stich3 [128]

Answer:

The quiz grades for class 1 have more variability than the quiz grades for class 2.

Step-by-step explanation:

8 0
3 years ago
A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a
zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}

Hence the answer is 0.1157

(ii) None is defective becomes

\begin{gathered} \lparen\frac{5}{6})^4=\frac{625}{1296} \\ =0.4823 \end{gathered}

hence the answer is 0.4823

(iii) All are defective

\begin{gathered} \lparen\frac{1}{6})^4=\frac{1}{1296} \\ =0.00077 \end{gathered}

(iv) At least one is defective

This is 1 - probability that none is defective

\begin{gathered} 1-\lparen\frac{5}{6})^4 \\ =1-\frac{625}{1296} \\ =\frac{671}{1296} \\ =0.5177 \end{gathered}

Hence the answer is 0.5177

3 0
1 year ago
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