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zavuch27 [327]
3 years ago
12

In an ice cream shop there is some money in a drawer. After 6 ice creams were sold, there were 70 euros left in the drawer. Afte

r a total of 16 ice creams were sold, there were 120 euros left in the drawer. How many euros were there in the drawer at the start?
Mathematics
1 answer:
Verizon [17]3 years ago
7 0

Answer: There were 40 euros in the drawer at the beginning.

Step-by-step explanation:

When we subtract 6 from 16, we get 10 more ice-creams were sold.

Similarly, we subtract 70 from 120, we get 50 euros was the total selling price of 10 ice-creams.

i.e. Selling price of 1 ice-cream = (50)÷10 =5 euros

Selling price of 6 ice-creams = 6 x 5 = 30 euros

Money in the drawer at the beginning = 70-30 = 40 euros

Hence, there were 40 euros in the drawer at the beginning.

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6 0
3 years ago
Point B is in between A and C in a segment. AB= 22 and BC=30 Find AC
dolphi86 [110]

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4 0
3 years ago
Kevin and Randy Muise have a jar containing 92 coins, all of which are either quarters or nickels. The total value of the coins
Artemon [7]
<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or

(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>
7 0
3 years ago
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