All categories

3 years ago

Sharon’s organization hopes to raise more

1 answer:

8 0

X >10,000

Hope that helps!
Remember the sign opens to the bigger number and the line underneath is only when that value is included.

You might be interested in

Molly has $45 in her wallet, which is 3 times as much money as her brother has. Write an equation to represent this situation, w

Lisa [10]

Answer:

the equation for this answer is 45(3)=a

5 0

3 years ago

Read 2 more answers

Determine value of a

S_A_V [24]

For this case we have that by definition of trigonometric relations that the sine of an angle is equal to the opposite leg to the angle on the hypotenuse. That is to say:

$Sin (43) = \frac {a} {26}$

Clearing the value of "a":

$a = 26 * sin (43)\\a = 26 * 0.68199836\\a = 17.73195736$

Rounding off we have:

17.7

Answer:

Option B

6 0

3 years ago

there has to be at least one operating path. Once a component fails on a path, that path is no longer operating. The reliability

Eva8 [605]

Answer:

$R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}$

For this case the reliability of the sytem would be given by:

$R= \prod_{i=1}^n R_i$

R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6

And replacing we got:

$R = 0.95*0.95*0.5*0.79*0.6= 0.21389$

Step-by-step explanation:

We can assume that the system work in series

If we have in general n units the reliability of the system is the probability that unit 1 succeeds and unit 2 succeeds and all of the other units in the system succeed. fror n units must succeed for the system to succeed. The reliability of the system is then given by:

$R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}$

For this case the reliability of the sytem would be given by:

$R= \prod_{i=1}^n R_i$

R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6

And replacing we got:

$R = 0.95*0.95*0.5*0.79*0.6= 0.21389$

8 0

3 years ago

1. What is the combined weight of the -Ib bags?

Airida [17]

Answer:

Step-by-step explanation:

CASNT HELP

7 0

3 years ago

A valve in a full 6000 gallon water tank is slowly opening. Water flows out of the tank through the valve. The flow rate in gall

Wittaler [7]

The volume of the gallon is 6000 gallon
the rate of water flow per min is f(t)=300t^2
a] amount of water that flowed in the first 7 minutes=7/60 hours will be:
f(7)=300(7/60)^2
solving the above we get
f(7)=7/12 gallons

b] The time taken for the tank to be empty will be as follows:
amount of water that will flow out for the tank to be empty will be 6000 gallons
thus,
6000=300t^2
this can be simplified to
20=t^2
t^2-20=0
solving this we get:
t=-2√5 or 2√5
the time taken for the tank to be empty will be t=2√5 hours=5.4721 hours

8 0

3 years ago

Read 2 more answers