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3 years ago

Simplify 12x^7y^3 divided by 6x^3y

Mathematics

1 answer:

ANEK [815]3 years ago

7 0

Answer:

2y^3x^7-3y

Step-by-step explanation:

I had the same problem on my test and got it right trust me

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ira [324]

Answer:

4 ounces

Step-by-step explanation:

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3 years ago

Given the information below, QRS is UVT similar to ? If so, give the scale factor.

viktelen [127]

$Look\ at\ the\ picture.\\\\\Delta QRS\sim\Delta UVT\ if\ \frac{|QR|}{|UV|}=\frac{|RS|}{|VT|}\\\\\frac{|QR|}{|UV|}=\frac{8}{18}=\frac{4}{9}\\\\\frac{|RS|}{|VT|}=\frac{16}{34}=\frac{8}{17}\\\\Answer:A.\ No,\ the\ triangles\ are\ not\ similar.$

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3 years ago

Susie is paying $540.15 every month for her $150,000 mortgage. If this is a 30 year mortgage, how much interest will she pay ove

GuDViN [60]

Answer:

17310.6

$540.15 multiply 30

because if they ask all in every month is 540.15

and she got 30 year

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3 years ago

The area of a rectangle is represented by the polynomial x^2+3x-6x-18. What are the length, width, and area of the rectangle if

Nitella [24]

Answer:

Length = 15

Width = 6

Area = 90

Step-by-step explanation:

Area of the rectangle = ${x}^{2} + 3x - 6x - 18$

Lets factorise the polynomial

$= > x(x + 3) - 6(x + 3)$

$= > (x + 3)(x - 6)$

We know that Area = Length × Width

Let the length be (x + 3) & width be (x - 6)

Its given in the question that x = 12. So putting the value of x gives ,

Length = $x + 3 = 12 + 3 = 15$

Width = $x - 6 = 12 - 6 = 6$

Area = Length × Width = 15 × 6 = 90

5 0

3 years ago

Graph the inverse circular function by hand, given f(x) = 3sin(2x) ;-pi/4 ≤ ≤pi/4

nasty-shy [4]

Part a)

a) The given function is

$f(x) = 3 \sin(2x)$

We let

$y = 3 \sin(2x)$

Interchange x and y.

$x= 3 \sin(2y)$

Solve for y;

$\frac{x}{3} = \sin(2y)$

$y = \frac{1}{2} { \sin}^{ - 1}( \frac{x}{3} )$

${f}^{ - 1}(x) = \frac{1}{2} { \sin}^{ - 1}( \frac{x}{3} )$

Part b) The range of f(x) refers to y-values for which f(x) exists.

The range of f(x) is

$- 3 \leqslant y \leqslant 3$

This is because the function is within y=-3 and y=3.

c) The range of

${f}^{ - 1} (x)$

$- \frac{ \pi}{4} \leqslant y \leqslant \frac{\pi}{4}$

The domain is -3≤x≤3

This is because the domain and range of a function and its inverse swaps.

Part d) The graph is shown in the attachment.

3 0

4 years ago