3d+ 3s = $21 because they bought three drinks and three snacks
Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
6[13-2(4+1)]
Solve what is in the bracket first.
Parenthesis first.
6[13-8-2]
6(3)
18
B. “Y = 15x” would be your answer. Y is your end balance and x is the weeks. For example, if x is 3 weeks, your equation would be 45 = 15*3. In this case, y would be 45. Need anymore help?
