Answer:
The perimeter (to the nearest integer) is 9.
Step-by-step explanation:
The upper half of this figure is a triangle with height 3 and base 6. If we divide this vertically we get two congruent triangles of height 3 and base 3. Using the Pythagorean Theorem we find the length of the diagonal of one of these small triangles: (diagonal)^2 = 3^2 + 3^2, or (diagonal)^2 = 2*3^2.
Therefore the diagonal length is (diagonal) = 3√2, and thus the total length of the uppermost two sides of this figure is 6√2.
The lower half of the figure has the shape of a trapezoid. Its base is 4. Both to the left and to the right of the vertical centerline of this trapezoid is a triangle of base 1 and height 3; we need to find the length of the diagonal of one such triangle. Using the Pythagorean Theorem, we get
(diagonal)^2 = 1^2 + 3^2, or 1 + 9, or 10. Thus, the length of each diagonal is √10, and so two diagonals comes to 2√10.
Then the perimeter consists of the sum 2√10 + 4 + 6√2.
which, when done on a calculator, comes to 9.48. We must round this off to the nearest whole number, obtaining the final result 9.
Answer:
Your(my) number is 40
Step-by-step explanation:
I. Given 80/something, + 13, * 5 = 75 when x is something
So [ 
+ 13 ]5 = 75
[ 
+ 65] = 75
= 75 - 65
= 10
400 = 10x
x = 40
II. Prove by replace 40 in x
[(80/40) + 13]5 = 75
[2 + 13] 5 = 75
(15)5 = 75
75 = 75 true
Ask me for anything.
Answer:
25,26,27,28,29
Step-by-step explanation:
The width of the rectangle is 2 meters
