Someone help and plz make sure it’s right :)

Pets R Us claims in their advertisement that they have the best price in town for ChowChow dog food. They sell 20-pound bags for

Ilya [14]

Answer:

stuff4pets has better price by 2 cents

Step-by-step explanation:

unit rate for chowchow is 16.95/20 = $.85 per pound

unit rate for stuff4pets is 24.95/30 = $.83 per pound

4 0

3 years ago

Read 2 more answers

8. Given: PQR and TSR are right triangles,

rewona [7]

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are scalene, right angled, isosceles, equilateral.

A right angled triangle is a triangle with one angle equals to 90°.

Statement Reason

∠PQR = ∠RST Given. ∠PQR = ∠RST = 90° (definition for right

angle triangle.

PQ = ST Given

PR ≅ RT Since R is the midpoint of PT, hence PR = RT

ΔPQR ≅ ΔTSR Side-angle-side triangle congruence theorem.

the Side-angle-side triangle congruence theorem

states that if two sides and an included angle of

one triangle is equal to two sides and an included

angle of another triangle, then the two triangles

are congruent. PQ=ST, PR = RT and ∠PQR = ∠TSR

3 0

3 years ago

At the local farmers market, it costs $10 to rent a stand and $7 for every hour you stay. If you pay a total of $38, how many ho

zhenek [66]

4 hours

Step by step:
$38 - 10 = 28
28/7 = 4

7 0

3 years ago

Read 2 more answers

Someone help me out please

uysha [10]

1 step (B): raise both sides of the equation to the power of 2.

$(\sqrt{x+3}-\sqrt{2x-1})^2=(-2)^2,\\ (x+3)-2\sqrt{x+3}\cdot \sqrt{2x-1}+(2x-1)=4,\\ 3x+2-2\sqrt{x+3}\cdot \sqrt{2x-1}=4$ .

2 step (A): simplify to obtain the final radical term on one side of the equation.

$-2\sqrt{x+3}\cdot \sqrt{2x-1}=4-3x-2,\\ -2\sqrt{x+3}\cdot \sqrt{2x-1}=2-3x,\\ 2\sqrt{x+3}\cdot \sqrt{2x-1}=3x-2$ .

3 step (F): raise both sides of the equation to the power of 2 again.

$(2\sqrt{x+3}\cdot \sqrt{2x-1})^2=(3x-2)^2,\\ 4(x+3)(2x-1)=(3x-2)^2$ .

4 step (E): simplify to get a quadratic equation.

$4(2x^2-x+6x-3)=(3x)^2-2\cdot 3x\cdot 2+2^2,\\ 8x^2+20x-12=9x^2-12x+4,\\ x^2-32x+16=0$ .

5 step (D): use the quadratic formula to find the values of x.

$D=(-32)^2-4\cdot 16=1024-64=960, \\ \sqrt{D} =8\sqrt{5} ,\\ x_{1,2}=\dfrac{32\pm 8\sqrt{5}}{2} =16\pm 4\sqrt{5}$ .

6 step (C): apply the zero product rule.

$x^2-32x+16=(x-16-4\sqrt{5}) (x-16+4\sqrt{5}) ,\\ (x-16-4\sqrt{5}) (x-16+4\sqrt{5}) =0,\\ x_1=16+4\sqrt{5} ,x_2=16-4\sqrt{5}$ .

Additional 7 step: check these solutions, substituting into the initial equation.

3 0

3 years ago

PLEASE I REALLY NEED HELP!

vagabundo [1.1K]

Answer:

$\frac{3}{28}$

Step-by-step explanation:

Probability (P) is calculated as

P = $\frac{requiredoutcome}{count}$

The first required outcome is a red sweet from a total of 3 + 5 = 8

P( red) = $\frac{3}{8}$

There are now 2 red left and a count of 7, since 1 has been eaten, thus

P( second red ) = $\frac{2}{7}$

P( red and red ) = $\frac{3}{8}$ × $\frac{2}{7}$ = $\frac{6}{56}$ = $\frac{3}{28}$

6 0

4 years ago