What is 3/7 divieded by 6 in a fraction

Help me with this math problem i don’t understand it

pav-90 [236]

Answer:

13meters

Step-by-step explanation:

c^2=a^2+b^2

12^2+5^2=169

find squareroot of 169 which is 13meters

4 0

2 years ago

If EFGH is a parallelogram, what is the value of x?

Vladimir [108]

Based on the property of the consecutive angles of a parallelogram, the value of x is calculated as: E. 37.

<h3>What are the Properties of the Angles of a Parallelogram?</h3>

In a parallelogram, the angles that are opposite to each other are congruent while consecutive angles are supplementary.

Angles F and G are consecutive angles and are therefore supplementary (have a sum of 180 degrees.)

Angle F + angle G = 180

4x - 2 + 34 = 180

4x + 32 = 180

4x = 180 - 32

4x = 148

x = 148/4

x = 37

Value of x is: E. 37.

Learn more about parallelogram on:

brainly.com/question/3050890

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4 0

2 years ago

In the formula p=kt find t when k=36 and p=144

stepan [7]

Answer:

t=4

Step-by-step explanation:

solve for t by deciding both sides by k.

then do 144/36 to get t.

4 0

2 years ago

Read 2 more answers

Nadia runs 8 miles each weekend. How many yards does Nadia run each weekend

luda_lava [24]

Answer:

14080 yds

Step-by-step explanation:

We know that 1 mile = 1760 yards

8 miles * 1760 yds/ 1 mile = (8*1760) yds=14080 yds

7 0

2 years ago

Read 2 more answers

If 180° < α < 270°, cos⁡ α = −817, 270° < β < 360°, and sin⁡ β = −45, what is cos⁡ (α + β)?

eduard

Answer:

$cos(\alpha+\beta)=-\frac{84}{85}$

Step-by-step explanation:

we know that

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

Remember the identity

$cos^{2} (x)+sin^2(x)=1$

step 1

Find the value of $sin(\alpha)$

we have that

The angle alpha lie on the III Quadrant

so

The values of sine and cosine are negative

$cos(\alpha)=-\frac{8}{17}$

Find the value of sine

$cos^{2} (\alpha)+sin^2(\alpha)=1$

substitute

$(-\frac{8}{17})^{2}+sin^2(\alpha)=1$

$sin^2(\alpha)=1-\frac{64}{289}$

$sin^2(\alpha)=\frac{225}{289}$

$sin(\alpha)=-\frac{15}{17}$

step 2

Find the value of $cos(\beta)$

we have that

The angle beta lie on the IV Quadrant

so

The value of the cosine is positive and the value of the sine is negative

$sin(\beta)=-\frac{4}{5}$

Find the value of cosine

$cos^{2} (\beta)+sin^2(\beta)=1$

substitute

$(-\frac{4}{5})^{2}+cos^2(\beta)=1$

$cos^2(\beta)=1-\frac{16}{25}$

$cos^2(\beta)=\frac{9}{25}$

$cos(\beta)=\frac{3}{5}$

step 3

Find cos⁡ (α + β)

$cos(\alpha+\beta)=cos(\alpha)*cos(\beta)-sin(\alpha)*sin(\beta)$

we have

$cos(\alpha)=-\frac{8}{17}$

$sin(\alpha)=-\frac{15}{17}$

$sin(\beta)=-\frac{4}{5}$

$cos(\beta)=\frac{3}{5}$

substitute

$cos(\alpha+\beta)=-\frac{8}{17}*\frac{3}{5}-(-\frac{15}{17})*(-\frac{4}{5})$

$cos(\alpha+\beta)=-\frac{24}{85}-\frac{60}{85}$

$cos(\alpha+\beta)=-\frac{84}{85}$

4 0

3 years ago