14 I think? (Tbh i really don’t know my bad)
Answer:
The answer to your question is ∠FSH = 42°; ∠NSF = 78°; ∠NSH = 120°
Step-by-step explanation:
Data
∠ FSH = 5x - 8
∠NSF = 9x - 12
∠NSH = 10x + 20
Process
1.- Write a equation to solve this problem
∠NSH = ∠NSF + ∠FSH
2.- Substitute values
10x + 20 = 9x - 12 + 5x - 8
3.- Solve for x
10 x - 9x - 5x = - 12 - 8 - 20
10x - 14x = - 12 - 28
- 4x = - 40
x = -40 / -4
x = 10
4.- Find the measure of all three angles
∠FSH = 5(10) - 8
= 50 - 8
= 42°
∠NSF = 9x - 12
= 9(10) - 12
= 90 - 12
= 78°
∠NSH = 10(10) + 20
= 100 + 20
= 120°
5.- Check the answers
120° = 78° + 42°
120° = 120°
The answers are correct
Answer: < > > =
Step-by-step explanation:
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
