1. 8^3 * 8^2, 8^5, and (2^3)^5
2. 6^9, and 6^5 x 6^4
Answer:
<u><em>−125a^(11)</em></u>
Step-by-step explanation:
<u><em>(−5a^(2)3a^(5) Then you solve</em></u>
<u><em>=−125a^(11)</em></u>
Answer:
ima take a wild guess and say a and c is right (im d u m b so i d k)
Step-by-step explanation:
Answer:
A product of factors is zero if and only if one or more of the factors is zero. That is, if ab = 0, then either a = 0 or b = 0 (or both).
Hence (x+3)(x+12) = 0 only if (x+3) = 0 or (x+12) = 0 or both. (x+3) = 0 when x = 3.(x+12) = 0 when x = 12.
Hence the values of x that make (x+3)(x+12) = 0 are x = 3 and x = 12.
