6*6-(3*3)-(2*2) is the answer
Step-by-step explanation:
let the numbers are:
a, b, and c
the equation would be:
a+b+c = 131
c = 4a
b = a+5
=>
a + a+5 +4a = 131
6a +5 = 131
6a = 131-5
6a = 126
a= 126/6
a = 21
b = a+5 = 21+5
b = 26
c = 4a = 4(21)
c = 84
Answer:
all real numbers
Step-by-step explanation:
you can create any value for y with a value for x, hence the range is "everything".
Answer:
So, this triangle PQR can be broken into two right triangles, PNQ and PNR, with legs PQ = 39, PN =15, and QN = ? and PR = 17, PN = 15, and NR =? respectively.
Let's solve for what is easier first:
Since we know that 5-15-17 is a Pythagorean triplet, we can infer that NR is 5....like I said earlier, it is a right triangle, so this guess holds true.
Here comes the interesting part:
Now, we have one part of QR, which is QN.
The other part can be solved by using the Pythagorean theorem.
It is (39^2-15^2)^(1/2)..which gives you 36, the square root of 1296, which happens to be the difference between the squares of 15 and 39.
SO, QR = QN + NR
5+36 = 41
QR = 41.
Hope this helps!
