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3 years ago

A tree is 8 meters tall . what is its height in feet

Mathematics

2 answers:

katovenus [111]3 years ago

5 0

Answer:

26.2467 foot

Step-by-step explanation:

jeka57 [31]3 years ago

5 0

26.247ft you’re welcome hope that helped :)

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20. Solve 4 - 2(b - 6) = 12<br><br>b = 2<br><br>b = 12<br><br>b = -2<br><br>b = -10

Maurinko [17]

Answer:

Option A is the correct option.

Solution,

$4 - 2(b - 6) = 12 \\ or \: 4 - 2b + 12 = 12 \\ or \: 4 + 12 - 2b = 12 \\ or \: 16 - 2b = 12 \\ or \: - 2b = 12 - 16 \\ or \: - 2b = - 4 \\ or \: b = \frac{ - 4}{ - 2} \\ b = 2$

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

Read 2 more answers

ind the surface area of a sphere with a radius of 12 cm. Approximate as 3.14 and round your answer to the nearest hundredth

Bezzdna [24]

The surface area of a sphere is:

A=4πr^2, if r=12 and π is approximated as 3.14 then

A≈4(3.14)(12^2)

A≈4(3.14)(144)

A≈576(3.14)

A≈1808.64 cm^2

5 0

3 years ago

Henri paid $10.75 for a calculator, $4.98 for copier paper, and $3.21 for folders. He paid with a $20 bill and got $1.06 in chan

Amiraneli [1.4K]

Answer:

10.75+4.98+3.21=18.94

20-18.94= 1.06

Step-by-step explanation:

up their

7 0

3 years ago

What is the perimeter of nadia's square ?

Nesterboy [21]

You forgot the picture of the square, please repost the question with the picture next time.

4 0

3 years ago

Read 2 more answers

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0

3 years ago