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2 years ago

14

Plzzzzzz helpppp!!!!! What is an equation of the line that passes through the point (4,2) and is perpendicular to the line 4x+3y

=21

1 answer:

Tom [10]2 years ago

4 0

Answer:

7

Step-by-step explanation:

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If an organism had 200 atoms of carbon-14 at death, how many atoms will be present after 14,325 years? Round the answer to the n

Lilit [14]

Answer:

35.34 atoms will be present after 14,325 years.

Step-by-step explanation:

Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.

To find : How many atoms will be present after 14,325 years?

Solution :

The half-life exponential function modeled is $N=N_o(\frac{1}{2})^{\frac{t}{h}}$

Where, $N_o=200$ is the initial atoms

N is the total number of atoms.

t=14,325 years is the time

h=5,730 years is the half-life time

Substitute the value in the formula,

$N=200(\frac{1}{2})^{\frac{14325}{5730}}$

$N=200(\frac{1}{2})^{2.5}$

$N=200(0.1767)$

$N=35.34$

Therefore, 35.34 atoms will be present after 14,325 years.

3 0

3 years ago

How man inches does the floor water rose in 1 day ? Answer as a fraction or round you decimal to the hundredths place

rodikova [14]

Answer:

there is no answer

Step-by-step explanation:

you didn't give a size on when it started or how much it grows per hour or something like that. your question is un solvable

6 0

2 years ago

4)) What is the volume? 19 yd 12 yd 12 yd

Zepler [3.9K]

Answer:

2,736

Step-by-step explanation:

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3 years ago

How do you find the normal approximation without using the continuity correction?

Dennis_Churaev [7]

Let's say you want to compute the probability $\mathbb P(a\le X\le b)$ where $X$ converges in distribution to $Y$ , and $Y$ follows a normal distribution. The normal approximation (without the continuity correction) basically involves choosing $Y$ such that its mean and variance are the same as those for $X$ .

Example: If $X$ is binomially distributed with $n=100$ and $p=0.1$ , then $X$ has mean $np=10$ and variance $np(1-p)=9$ . So you can approximate a probability in terms of $X$ with a probability in terms of $Y$ :

$\mathbb P(a\le X\le b)\approx\mathbb P(a\le Y\le b)=\mathbb P\left(\dfrac{a-10}3\le\dfrac{Y-10}3\le\dfrac{b-10}3\right)=\mathbb P(a^*\le Z\le b^*)$

where $Z$ follows the standard normal distribution.

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3 years ago

Charles and his brother are sharing the cost of a video game. The video game costs $30.70. If Charles saved $20 to buy the game

Norma-Jean [14]

hi can we be friends? if you like it do

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2 years ago