Answer:
Greatest sack = 42
1 candy bar and 3 lollipops
<em></em>
Step-by-step explanation:
Represent Candy bars with C and Lollipops with L


Solving (a): Greatest number of treat sacks
To solve this, we simply calculate the GCF of C and L


Hence, the GCF is


Hence, greatest number of sack is 42
Solving (b): Number of treat in each sack.
To do this, we simply divide the number of C and L by the calculated GCF
For C:



For L:



<em>Hence, 1 candy bar and 3 lollipops</em>
Answer/Step-by-step explanation:
Given:
m<EFH = (5x + 1)°
m<HFG = 62°
m<EFG = (18x + 11)°
Required:
1. Value of x
2. m<EFH
3. m<EFG
SOLUTION:
1. Value of x
m<EFH + m<HFG = m<EFG (angle addition postulate)
(5x + 1) + 62 = (18x + 11)
Solve for x using this equation
5x + 1 + 62 = 18x + 11
5x + 63 = 18x + 11
Subtract 18x from both sides
5x + 63 - 18x = 18x + 11 - 18x
-13x + 63 = 11
Subtract 63 from both sides
-13x + 63 - 63 = 11 - 63
-13x = -52
Divide both sides by -13
-13x/-13 = -52/-13
x = 4
2. m<EFH = 5x + 1
Plug in the value of x
m<EFH = 5(4) + 1 = 20 + 1 = 21°
3. m<EFG = 18x + 11
m<EFG = 18(4) + 11 = 72 + 11 = 83°
We have 9, 9.86, 9.42
So in order from least to greatest it would be: 9, 3 times pi, pi squared
Area of the composite shape = 292 yd²
Solution:
The shape is splitted into two rectangles.
The reference image of the answer is attached below.
Length of the top rectangle = 21 yd
Width of the top rectangle = 29 yd – 22 yd = 7 yd
Length of the side rectangle = 29 yd
Width of the side rectangle = 26 yd – 21 yd = 5 yd
Area of the figure = Area of the top rectangle + Area of the side rectangle
= (length × width) + (length × width)
= (21 × 7) + (29 × 5)
= 147 + 145
= 292
Area of the composite shape = 292 yd²