MN = 6 in
add the parts of the ratio, 1 + 2 + 3 = 6
divide AB by 6 to find 1 part of the ratio
= 3 ← 1 part
AM = 3 in ← 1 part
MN = 2 × 3 = 6 in ← 2 parts
NB = 3 × 3 = 9 in ← 3 parts
and 3 + 6 + 9 = 18 in = AB
For this problem, we use the approach of ratio and proportion. Assuming that the given ratio of 444 days per 230 km is constant all throughout, we can determine the number of days or distance as long as one of the two is given. In this case, the solution is as follows:
444 days/230 km = 161616 days/distance
Distance = 83,720 km
Answer:
The probability that a radio selected at random will last from 600 to 700 hours is 0.3413
Step-by-step explanation:
The playing life of a Sunshine radio is normally distributed
Mean =
Standard deviation =
We are supposed to find the probability that a radio selected at random will last from 600 to 700 hours i.e.P(600<x<700)
Formula:
At x = 600

Z=0

At x = 700

Z=1


Hence the probability that a radio selected at random will last from 600 to 700 hours is 0.3413
Answer:
Where is the triangle?
you might have to add a picture or a worded problem
Step-by-step explanation: