3 years ago

Pending on your answer

Mathematics

2 answers:

DedPeter [7]3 years ago

6 0

Answer:

Step-by-step explanation:

7 + 5 + 6 = 18 miles

zysi [14]3 years ago

5 0

Answer:

Step-by-step explanation:

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egoroff_w [7]

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3 years ago

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GarryVolchara [31]

Answer:so I can help you with that I only in sixth grade

Step-by-step explanation:

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3 years ago

Indicate in standard form the equation of the line passing through the given point and having the given slope.. . B(6, 2), m = -

Leni [432]

General form of Equation of straight line is:
y=m x + b
m=-1/2 passing through (6,2)
plug these values in general form,we get
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3 years ago

In ΔQRS, the measure of ∠S=90°, the measure of ∠Q=71°, and RS = 2.5 feet. Find the length of SQ to the nearest tenth of a foot

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Step-by-step explanation:

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3 years ago

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Alex Ar [27]

The Lagrangian is

$L(x,y,z,\lambda,\mu)=3x-y-3z+\lambda(x+y-z)+\mu(x^2+2z^2-1)$

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$L_y=-1+\lambda=0\implies\lambda=1$

$L_z=-3-\lambda+4\mu z=0$

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$L_\mu=x^2+2z^2-1=0\implies x^2+2z^2=1$

Since we know $\lambda=1$ , we have

$L_x=0\implies4+2\mu x=0\implies x=-\dfrac2\mu$
$L_z=0\implies-4+4\mu z=0\implies z=\dfrac1\mu$
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$L_\lambda=0\implies y=z-x\implies y=\pm\dfrac3{\sqrt6}$

So there are two critical points, $\left(-\dfrac2{\sqrt6},\dfrac3{\sqrt6},\dfrac1{\sqrt6}\right)$ and $\left(\dfrac2{\sqrt6},-\dfrac3{\sqrt6},-\dfrac1{\sqrt6}\right)$ , which give a minimum value of $-2\sqrt6$ and a maximum value of $2\sqrt6$ , respectively.

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3 years ago