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allsm [11]
3 years ago
6

Adding 0 to any number leaves it unchanged. For example a + 0 = a.

Mathematics
2 answers:
diamong [38]3 years ago
4 0

Answer:

true

Step-by-step explanation:

❤️✨

m_a_m_a [10]3 years ago
4 0

Yep that's correct XD

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How will the solution of the system y > 2x + Two-thirds and y < 2x + One-third change if the inequality sign on both inequ
blagie [28]

Answer:

Step-by-step explanation:344x-5-p-0-9-but=pmc+m2 something like that

8 0
2 years ago
Which of the following represents 4x^5/6 in radical form
mash [69]
Remember, order of operations
exponent before multiply

so 4x^5/6=4 times x^5/6
simplify the x^5/6 first

remember
x^\frac{m}{n}=\sqrt[n]{s^m}

so
x^\frac{5}{6}=\sqrt[6]{x^5}

so
4x^\frac{5}{6}=4\sqrt[6]{x^5}
<span />
6 0
3 years ago
Find the upper limit for the zeros of the function P(x)=4x^4+8x^3-7x^2-21x-9
pishuonlain [190]

Answer:

OPTION B - 2

Step-by-step explanation:

What is the upper limit for the zeros of the function P(x) = 4x^4 + 8x^3 - 7x^2 - 21x - 9. Ans: 2 is an upper limit. Use synthetic division. and the remainder are all positive, 2 is an upper limit.

3 0
2 years ago
Plz hurry!!!! thank you!!!!
Nikitich [7]

Answer:

Area of trapezium = 4.4132 R²

Step-by-step explanation:

Given, MNPK is a trapezoid

MN = PK and ∠NMK = 65°

OT = R.

⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).

Now, sum of interior angles in a quadrilateral of 4 sides = 360°.

⇒ x + x + 65° + 65° = 360°

⇒ x = 115°.

Here, NS is a tangent to the circle and ∠NSO = 90°

consider triangle NOS;

line joining O and N bisects the angle ∠MNP

⇒ ∠ONS = \frac{115}{2} = 57.5°

Now, tan(57.5°) = \frac{OS}{SN}

⇒ 1.5697 = \frac{R}{SN}

⇒ SN = 0.637 R

⇒ NP = 2×SN = 2× 0.637 R = 1.274 R

Now, draw a line parallel to ST from N to line MK

let the intersection point be Q.

⇒ NQ = 2R

Consider triangle NQM,

tan(∠NMQ) = \frac{NQ}{QM}

⇒ tan65° = \frac{NQ}{QM}

⇒ QM = \frac{2R}{2.1445}

QM = 0.9326 R .

⇒ MT = MQ + QT

          = 0.9326 R + 0.637 R  (as QT = SN)

⇒ MT = 1.5696 R

⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R

Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).

⇒ A = (\frac{NP + MK}{2}) × (ST)

       = (\frac{1.274 R + 3.1392 R}{2}) × 2 R

       = 4.4132 R²

⇒ Area of trapezium = 4.4132 R²

5 0
3 years ago
#1 what is the population and what is the sample?
klemol [59]

Population: All high school students.   We're interested in the health of <em>all</em> of them, that's our population.

Sample: Athletes who were surveyed.  Our sample is where we got our actual data.

4 0
3 years ago
Read 2 more answers
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