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Liula [17]
3 years ago
8

Solve for x x^2-2x-2=0

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0
I believe it’s x=1+√3,1−√3
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the area of a square with a side length of 9x  

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2 15.50 50

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Musya8 [376]

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The answer should be about 114.

Step-by-step explanation:

Of you look at the shape of the other angles. B and D seem to be about 90 and the shape of A is just a little bit bigger than ninety. I started by adding 78, 90, and 90 together which gave me 246. Then I subtracted 246 from 360 which gave me 114. I had estimated the answer to be around 110.

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2 years ago
When consumers apply for credit, their credit is rated using FICO (Fair, Isaac, and Company) scores. Credit ratings are given be
Flura [38]

Answer:

a) The 99% confidence interval would be given by (589.588;731.038)

b) If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The data is:

661 595 548 730 791 678 672 491 492 583 762 624 769 729 734 706

Part a

Compute the sample mean and sample standard deviation.  

In order to calculate the mean and the sample deviation we need to have on mind the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n}  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}  

=AVERAGE(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

On this case the average is \bar X= 660.313

=STDEV.S(661, 595, 548, 730, 791, 678, 672, 491 ,492, 583, 762 ,624 ,769, 729, 734, 706)

The sample standard deviation obtained was s=95.898

Find the critical value t* Use the formula for a CI to find upper and lower endpoints

In order to find the critical value we need to take in count that our sample size n =16<30 and on this case we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. The degrees of freedom are given by:

df=n-1=16-1=15

We can find the critical values in excel using the following formulas:

"=T.INV(0.005,15)" for t_{\alpha/2}=-2.95

"=T.INV(1-0.005,15)" for t_{1-\alpha/2}=2.95

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}  

And if we find the limits we got:

660.313- 2.95\frac{95.898}{\sqrt{16}}=589.588  

[tex]660.313+ 2.95\frac{95.898}{\sqrt{16}}=731.038/tex]  

So the 99% confidence interval would be given by (589.588;731.038)

Part b

If we see the confidence interval the 620 is included on the interval we don't have enough evidence to reject the rating is 620. But since we need a score that at least 620 and our lower limit is 589.588 we cant conclude that all the clients would have a score that at least of 620.  

4 0
3 years ago
How can you make 0.40 into a fraction??
melamori03 [73]
<h3>2/5 is your answer. </h3><h3>▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓▓</h3>

☞ First, 0.40 is the same as 40/100.

But we are not done.

<u>Now, doing this you need to find the GCF (Greatest common factor) of 40, 100.</u>

2 x 2 x 5 = 20.

☞ So our GCF is 20.

Divide both the numerator and the denominator by the GCF.

40 ÷ 20 / 100 ÷ 20.

<h2>Simplify to get ☞ 2/5.</h2><h2>▬▬ι══════════════ι▬▬</h2>

Best of luck on your assignment!

▬▬ι══════════════ι▬▬

- Emacathy | Top Answerer ♫♪.ılılıll|̲̅̅●̲̅̅|̲̅̅=̲̅̅|̲̅̅●̲̅̅|llılılı.♫♪

<h2 />

8 0
3 years ago
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