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Liula [17]
3 years ago
8

Solve for x x^2-2x-2=0

Mathematics
1 answer:
Nostrana [21]3 years ago
6 0
I believe it’s x=1+√3,1−√3
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I have a square with a side of 5.25 in. There is a circle inside this square that is big enough to touch all four sides. What is
DENIUS [597]

Answer:

5.9125in^2

Step-by-step explanation:

Step one:

Given data

Dimension of square= 5.25 in

Area of sqaure= 5.25^2= 27.5625  in^2

We are told that the sides of the circle touch the sides of the square

hence the diameter of the circle is 5.25in

radius= 5.25/2= 2.625 in

Area of  circle= πr^2

Area of circle = 3.142*2.625^2

Area of circle=3.142*6.890625

Area of circle= 21.65 in^2

Step two:

The area that is not inside the circle

=Area of square-Area of circle

=27.5625- 21.65

=5.9125in^2

4 0
3 years ago
I need help with this homework question
salantis [7]
If you divide 64/16, that equals 4, then you multiply 4*3 and your answer is 12. It looks something like this (for "showing your work" purposes);

64/16=4
4 x 3=12
answer=16 cups of sugar for 64 bags of tea

4 0
3 years ago
Read 2 more answers
During dance practice, Sasha drank 21⁄2 pints of water, and on the way home she drank 1⁄2 cup of water. How much water did she d
snow_tiger [21]

5 1/2 cups or 2 3/4 pints

4 0
3 years ago
Help
SpyIntel [72]

Answer:

the admininstrative assistant can type 70 word in a minute i think

Step-by-step explanation:

5 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
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