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scZoUnD [109]
3 years ago
7

Find the unit rate: $1.32 for 12 ounces plz help

Mathematics
1 answer:
iren2701 [21]3 years ago
3 0

Answer:

<h2>$0.11 per ounce</h2>

Step-by-step explanation:

$1.32/12oz = x/1oz

Cross Multiply.

1.32 = 12x

Divide both side by 12.

1.32/12 = x

Convert to decimal.

$0.11 for 1 ounce

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11. Higher Order Thinking Using what you know
Lynna [10]

Answer:

m∠1 + m∠3 = m∠2 + m∠4

Step-by-step explanation:

In the figure attached,

In the given trapezoid if two sides AB and CD are parallel and AD is a transverse,

m∠1 + m∠3 = 180°

Similarly, if AB and CD are parallel and BC is a transverse,

m∠2 + m∠4 = 180°

Therefore, m∠1 + m∠3 = m∠2 + m∠4 is the relation between these angles.

6 0
3 years ago
A 15 kilogram object is suspended from the end of a vertically hanging spring stretches the spring 1/3 meters. At time t = 0, th
Yuri [45]

Answer:

15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

y(0)=0, y'(0)=0

Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: F_{r} (t) that correspond to the force of resistance on the mass by the action of the spring and F(t) that is an external force with unknown direction (that does not specify in the enounce).

For determinate F_{r} (t) we can use Hooke's Law given by the formula F_{r} (t) = k y(t) where k correspond to the elastic constant of the spring and y(t) correspond to  the relative displacement of the mass-spring system with respect of his rest state.

We know from the problem that an 15 Kg mass stretches the spring 1/3 m so we apply Hooke's law and obtain that...

k = \frac{F_{r}}{y} = \frac{mg}{y} = \frac{15 Kg (9.81 \frac{m}{s^{2} } )}{\frac{1}{3} m}  = 441.45 \frac{N}{m}

Now we apply Newton's 2nd Law and obtaint that...

F_{r} (t) ± F(t) = ma(t)

F_{r} (t) = ky(t) = 441.45y(t)

F(t) = 170 cos(5t)

m = 15 kg

a(t) = \frac{d^{2}y(t)}{dt^{2} }

Finally... 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = ± 170 cos(5t)

We know from the problem that there's not initial displacement and initial velocity, so... y(0)=0 and y'(0)=0

Finally the Initial Value Problem that models the situation describe by the problem is

\left \{ 15\frac{d^{2}y(t)}{dt^{2} }  - 441.45y(t) = \frac{+}{} 170 cos(5t) \atop {y(0)=0, y'(0)=0\right.

6 0
3 years ago
9-3 divided by 4+2•12+6 divided by 2•3
Dimas [21]

Answer:

1/34

Step-by-step explanation:

9-3= 6

(4+2x12+6)=34

6/34= 3/17 which is .1764......

3/17 divide by (2x3)= 1/34

6 0
4 years ago
Read 2 more answers
The original equation is this:
likoan [24]

Answer:

x=0, x=5

Step-by-step explanation:

x²-5x+8=8

x²-5x=0

x(x-5)=0

x=0 , x-5=0

x=5

3 0
2 years ago
How long does it take to travel 300 miles at 15 miles per hour
bearhunter [10]
It takes 20 miles per hour to travel 300 miles
8 0
3 years ago
Read 2 more answers
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