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MAXImum [283]
3 years ago
5

16x+9=9y-2x Solve for y

Mathematics
1 answer:
Novay_Z [31]3 years ago
8 0
Y=2x+1... I hope this helps love! :)
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$24,000 at 5% for 5 years . $_
Dmitry_Shevchenko [17]

Answer:

$18,570.7425

Step-by-step explanation:

24,000 * 0.95 5 times, this will give you the 5% for 5 years

8 0
3 years ago
Use cylindrical coordinates. find the volume of the solid that is enclosed by the cone z = x2 + y2 and the sphere x2 + y2 + z2 =
sashaice [31]
Let R be the solid. Then the volume is

\displaystyle\iiint_R\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta

which follows from the facts that

\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}\implies\mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm d\zeta
(by computing the Jacobian)

and

z=x^2+y^2=r^2\implies z+z^2=72\implies z=-9\text{ or }z=8
(we take the positive solution, since it's clear that R lies above the x-y plane)
r^2+z^2=72\implies z=\pm\sqrt{72-r^2}
(again, taking the positive root for the same reason)
z=r^2\implies 8=r^2\implies r=\sqrt8

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}\int_{\zeta=r^2}^{\zeta=\sqrt{72-r^2}}r\,\mathrm d\zeta\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}r(\sqrt{72-r^2}-r^2)\,\mathrm dr
=\displaystyle2\pi\int_{r=0}^{r=\sqrt8}(r\sqrt{72-r^2}-r^3)\,\mathrm dr
=\dfrac{32(27\sqrt2-35)\pi}3
7 0
3 years ago
What is the inverse of this operation x-3
omeli [17]

Answer:

1/ x-3

Step-by-step explanation:

The inverse of a number or expression means one divided by the number .

So inverse of x-3 is

1/ x-3

5 0
3 years ago
Is this right? please help me
Dimas [21]

Answer: i would help but the picture is blank .

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Which graph represents the function f(x)=-|x|-2?
skad [1K]

Answer:

ind the absolute value vertex. In this case, the vertex for y=−|x|−2 is (0,−2).

(0,−2)

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(−∞,∞)

Set-Builder Notation:  {x|x ∈ R}

For each x value, there is one y value. Select few x values from the domain. It would be more useful to select the values so that they are around the x value of the absolute value vertex.

 x     y

−2   −4

−1    −3

 0   −2

 1    −3

 2   −4

Step-by-step explanation:

5 0
3 years ago
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