Answer: B.10
Step-by-step explanation:
0.765 (100) + .06 (.0765 x 100)
76.5 + .06 (76.5)
76.5 + 4.59 = 81.09 Chris will pay $81.09
A better way ( if you don't care to know the tax just the bottom line of what it will cost) would be to do:
0.765x x 1.06 = 76.5 x 1.06 = $81.09 too.
Why the 1 in front of the .06? The one includes the price of the coat so you don't have to add the tax on after.
Think about it like this. When you buy something you pay (even with an employee
discount) for all of it (100%) + the tax (in this case, it's 6%) So you pay 106% of the cost of the item. 106% = 1.06
I think is c that what i think
Answer:
the lowest passing score would be x = 298
Step-by-step explanation:
School wishes that only 2.5 percent of students taking test pass
We are given
mean= 200,
standard deviation = 50
We need to find x
The area under the curve can be found by:
2.5 % = 0.025
So, 1- 0.025 = 0.975
We need to find the value of z for which the answer is 0.975
Looking at the z-score table, the value of z is: 1.96
Now, using the formula:
z = x - mean/standard deviation
1.96 = x - 200/50
=> 1.96 * 50 = x-200
98 = x - 200
=> x = 200+98
x = 298
So, the lowest passing score would be x = 298
Answer:
A.)
H0: μ ≤ 31
H1: μ > 31
B.)
H0: μ ≥ 16
H1: μ < 16
C.)
Right tailed test
D.)
If Pvalue is less than or equal to α ; we reject the Null
Step-by-step explanation:
The significance level , α = 0.01
The Pvalue = 0.0264
The decision region :
Reject the null if :
Pvalue < α
0.0264 > 0.01
Since Pvalue is greater than α ; then, we fail to reject the Null ;
Then there is no significant evidence that the mean graduate age is more Than 31.
B.)
H0: μ ≥ 16
H1: μ < 16
Null Fluid contains 16
Alternative hypothesis, fluid contains less than 16
One sample t - test
C.)
Null hypothesis :
H0 : μ ≤ 12
. The direction of the sign in the alternative hypothesis signifies the type of test or tht opposite direction of the sign in the null hypothesis.
Hence, this is a right tailed test ; Alternative hypothesis, H1 : μ > 12
d.)
If Pvalue is less than or equal to α ; we reject the Null.
