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abruzzese [7]
2 years ago
12

If y varies inversely as x and y=23 when x=8 find y when x=4

Mathematics
1 answer:
valina [46]2 years ago
5 0
<h2>INVERSE VARIATION</h2>

<em>E</em><em>Q</em><em>U</em><em>A</em><em>T</em><em>I</em><em>O</em><em>N</em><em>:</em><em> </em><em> </em><em> </em><em> </em>

y =  \frac{k}{x}

<em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em>

First, find the constant of variation <em>k</em> using the formula k=xy.

23 =  \frac{k}{8}

k = (8)(23)

k = 184

<em>–</em><em>–––––––</em>

Then, find <em>y</em> if <em>x</em> is equal to four using the formula y=184/x.

y =  \frac{184}{x}

y =  \frac{184}{4}

y = 46

<em>F</em><em>i</em><em>n</em><em>a</em><em>l</em><em> </em><em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em>

<h2>y = 46</h2>
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I am having a conflict with my family what is 7-1×0+3÷3 = ?
ryzh [129]
Follow PEMDAS.

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Alright, do multiplication first, then division. Then, do subtraction then addition.

7-1*0+3/3= \\ 7-0+3/3= \\ 7 - 0 + 1= \\ 7 + 1 = 8 \\ 7-1*0+3/3 =8

Hope this helped!
6 0
3 years ago
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fenix001 [56]

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brilliants [131]
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2 years ago
You randomly draw twice from this deck of cards
Serggg [28]

The probability of not drawing C in neither draw is P = 0.5

<h3>How to get the probability?</h3>

All the cards have the same probability of being drawn, in this case, our set of cards is {F, D, C, G}

The probability of not drawing C is equal to the probability of drawing F, D or G. So we have 3 options out of 4, then the probability is:

p = 3/4.

Now we draw another, this time there are 3 cards, one of these is C, and the other two cards are not C. Then the probability of not drawing C again is equal to 2 over 3.

q = 2/3.

The joint probability (for both of these events to happen) is equal to the product of the individual probabilities:

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If you want to learn more about probability, you can read:

brainly.com/question/251701

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