Solve for t.

A commercial building has seven levels of car parking spaces. Each level has four rows and each row has 38 car spaces. How many

tatyana61 [14]

So, all we have to do here is multiply:

First, the amount of car spaces by the amount of rows:

38 x 4 = 152

This is the number of parking spots per level.

Then, the number of levels by the number of parking spots on each level:

152 x 7 = 1064

So, a total of 1,064 cars can be parked in this building!

8 0

3 years ago

A microwave manufacturing company has just switched to a new automated production system. Unfortunately, the new machinery has b

baherus [9]

Answer:

Null hypothesis: $\mu \leq 6$

Alternative hypothesis: $\mu > 6$

$t=\frac{6.5-6}{\frac{1.5}{\sqrt{36}}}=2$

$df=n-1=36-1=35$

$t_{crit}=1.690$ with the excel code:"=T.INV(0.95,35)"

$t_{crit}=1.306$ with the excel code:"=T.INV(0.90,35)"

$p_v =P(t_{(35)}>2)=0.0267$

If we compare the p value and the significance level given $\alpha=0.05,0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the true mean it's significantly higher than 6 at 5% and 10% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=6.5$ represent the mean time for the sample

$s=1.5$ represent the sample standard deviation for the sample

$n=36$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05,0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 6 days, the system of hypothesis would be:

Null hypothesis: $\mu \leq 6$

Alternative hypothesis: $\mu > 6$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{6.5-6}{\frac{1.5}{\sqrt{36}}}=2$

Critical value and P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=36-1=35$

In order to calculate the critical value we need to find a quantile on the t distribution with 35 degrees of freedom that accumulates $\alpha$ on the right. Using the significance level of 0.05 we got:

$t_{crit}=1.690$ with the excel code:"=T.INV(0.95,35)"

And using the significance of 0.1 we got

$t_{crit}=1.306$ with the excel code:"=T.INV(0.90,35)"

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(35)}>2)=0.0267$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05,0.1$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the true mean it's significantly higher than 6 at 5% and 10% of significance.

6 0

3 years ago

Help me please

Goshia [24]

Midpoint is (-2 , -0.5)

6 0

3 years ago

I'll give you brainlies if you help me on this!

ryzh [129]

Answer:

5/4 ounces.

Step-by-step explanation:

There are 4 marks. So 1/4 is the smallest one. There are 5 of them. 5x1/4 is 5/4 or 1 1/4

3 0

2 years ago

Read 2 more answers

Help on 12 Aswell please

aev [14]

108 divided by each cup of fruit and seltzer will get you how many cups per serving and for C divide how many cups of seltzer with cups of orange juice

6 0

3 years ago