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Elden [556K]
3 years ago
6

Please answer this one question for me!!!!!!!

Mathematics
2 answers:
sergey [27]3 years ago
4 0
I’m pretty sure the correct answer is false I’m so sorry if it is incorrect
I am Lyosha [343]3 years ago
4 0

Answer:

answer is

False

The picle ball the server must keep both feet behind the back serving line. false

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If a linear function y = 2x + 3 moves down 4 units, and then moves right 4 units to changes into a new function y = ax + b, find
11111nata11111 [884]

Answer:

a= 2 b=-9

Step-by-step explanation:

Please refer to the picture attached.

You can clarify the answer by substituting random points like (0,0) and transformed point

E. G. (0, - 4) in step 1 and (4,0) in step 2 into the original equation and transformed equation for checking.

6 0
4 years ago
Please view the images that go in order and help me for brainlist :P
serg [7]
I think it’s the third one hope this helps
3 0
3 years ago
Read 2 more answers
Write the given expression as an algebraic expression in x. tan(2 cos^-1(x))
miv72 [106K]
\bf tan\left[ 2cos^{-1}(x) \right]\implies tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]
\\\\\\
\textit{if we say }cos^{-1}\left( \frac{x}{1} \right)=\theta\textit{  that means }tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]\iff tan(2\theta)\\\\
-----------------------------\\\\
cos^{-1}\left( \frac{x}{1} \right)=\theta\implies cos(\theta)=\cfrac{x}{1}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}\\\\
-----------------------------\\\\


\bf \textit{again, using the pythagorean theorem to get the opposite side}
\\\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\implies \pm\sqrt{1^2-x^2}=b
\\\\\\
\pm\sqrt{1-x^2}=b\\\\
-----------------------------\\\\
tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\cdot \frac{\pm\sqrt{1-x^2}}{x}}{1-\left( \frac{\pm\sqrt{1-x^2}}{x} \right)^2}
\\\\\\

\bf tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{1-\frac{1-x}{x}}\implies 
tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{\frac{x-1+x}{x}}
\\\\\\
tan(2\theta)=\cfrac{\pm2\sqrt{1-x^2}}{x}\cdot \cfrac{x}{2x-1}
\implies 
tan(2\theta)=\cfrac{\pm 2\sqrt{1-x^2}}{2x-1}


6 0
4 years ago
What is the rate of the trains in mph?
Fynjy0 [20]
I really don’t know sorry I would help you but I can genesis hdbdbhs hebdbh
5 0
3 years ago
Here you go the brainless
Aleksandr-060686 [28]
Area of parallelogram
= L × H
= 23 × 13
= 299 feet²
5 0
3 years ago
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