Answer: Final temperature of the gas will be 330 K.
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
(At constant volume and number of moles)
where,
= initial pressure of gas = 1.00 atm
= final pressure of gas = 1.13 atm
= initial temperature of gas = 
K
= final temperature of gas = ?
Therefore, the final temperature of the gas will be 330 K.
Answer:
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Explanation:
None. To bind with an hydrogem atom, the carbon needs to ''share'' one of it's valence electron's with the hydrogen's valence electron. Therefore, forming 4 bounds means the carbon atom will share it's 4 valence electrons and there will be no lone electrons.
The wt% of KOH = 45%
This implies that there is 45 g of KOH in 100 g of the solution
Density of the solution is given as 1.45 g/ml
Therefore, the volume corresponding to 100 g of the solution is
= 100 g * 1 ml /1.45 g = 68.97 ml = 0.069 L
Now concentration of the concentrated KOH solution is:
Molarity = moles of KOH/vol of solution
= (45 g/56.105 g.mol-1)/0.069 L = 11.6 M
Thus,
Initial KOH concentration M1 = 11.6 M
Initial volume = V1
Final concentration M2 = 1.20 M
Final volume V2 = 250 ml
M1*V1= M2*V2
V1 = M2*V2/M1 = 1.20*250/11.6 = 25.9 ml = 26 ml
