The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
Read more on average of integers;
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9 to the 3rd power is 729
And 2 to the 5th power is 32. You multiple 9, 3 times. 9 times 9 times 9 and you multiply 2, five times. 2 times 2 times 2 times 2 times 2
3088.22813276
hope this helps, you could've entered this into a calculator for next time.
Answer:
Any number smaller than 2
Step-by-step explanation:
You would graph this by wrighting a solid, filled in circle with an arrow point toward the negative numbers, because those numbers are smaller than 2
Answer:
C
Step-by-step explanation:
Parallel line slopes are always the same.
