F(x) = -2(x - 3)² + 2
f(x) = -2(x - 3)(x - 3) + 2
f(x) = -2[x(x - 3) - 3(x - 3)] + 2
f(x) = -2[x(x) - x(3) - 3(x) - 3(-3)] + 2
f(x) = -2(x² - 3x - 3x + 9) + 2
f(x) = -2(x² - 6x + 9) + 2
f(x) = -2(x²) - 2(-6x) - 2(9) + 2
f(x) = -2x² + 12x - 18 + 2
f(x) = -2x² + 12x - 16
Answer: 62unit^2
Explanation
Answer:The function v(x) has the largest value when x = 4.
Solution:
x=4;
e(4) = 4^2 + 6×4 + 21=16+24+21=61
m(4) = 8×4=32
v(4) = 31×4=124
v(4)>e(4)>m(4)
Therefore,The function v(x) has the largest value when x = 4.
The equation is/// k = (1/4)j
Answer:
function is f(x) = x+6
and the missing outputs are 19, 24 and 27
