A golf ball is hit on the moon so that

1 answer:

5 0

I am just not sure if I did this properly. My professor hasn't really gone over when to use the range equation but I would assume range would equal the distance traveled therefore can be used for this problem. If not the how would I go about solving this? I did 1/6*9.8=1.63 for g on the moon Then used R=(Vi^2sin2theta)/g so on the moon R=((28^2)sin2*35)/1.63=452m

Please Brainliest..? thx

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50 points!!!!

almond37 [142]

Answer:

5 inches

Step-by-step explanation:

Area of the cake:

1 slice = 13 in²
6 slices = 13 in² * 6 = 78 in²

Area circle: πr²

Solve for r:

78 = πr²
r² ≈ 24.84
r ≈ 5

-Chetan K

8 0

2 years ago

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3(ck) = (3c)k ???? show all work

Rus_ich [418]

Step-by-step explanation:

3(ck) = (3c)k - it's an Associative Property of multiplication

3 · (c · k) = (3 · c) · k

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3 years ago

The water level varies from 12 inches at low tide to 52 inches at high tide. Low tide occurs at 9:15 a.m. and high tide occurs a

balandron [24]

52 inches - 12 inches = 40 inches
amplitude: a = 40 inches / 2 = 20

f(x)=20cos(bx)+c
the value of c is 32... since the centre of the has been moved up 32 units

the minimum amplitude = 32 - 20 = 12
the maximum amplitude = 32 + 20 = 52

f(x)=20cos(bx)+32
if the curve takes 6 1/4 hours from low to high tides (9:15 am to 3:30 pm) then it will take 12 1/2 hours to complete a full cycle.

adjust the period by converting 12 1/2 hours to an angle measure.

360°/12 = 30°
30° / 12 = 15°

12 1/2 = 360° + 15° = 375°

f(x) = 20 cos(375°) + 32
f(x) = 20 * 0.97 + 32
f(x) = 19.4 + 32
f(x) = 51.4

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3 years ago

[(√4 + 3)2 – 9] / (√9 – 1)3 * 2

Ket [755]

Answer:

$\frac{1}{12}$