If the width is w and the length is l, then 2w-2=l and 2w+2l=72 (using the perimeter equation). Plugging 2w-2 in for l, we get 2w+(2w-2)*2=72 and 6w-4=72. Adding 4 to both sides, we get 6w=76. After that, we divide both sides by 6 to get 74/6=w. Since l=2w-2=136/6, we get (136/6)(74/6)=656.75=area
Answer:
19.8839
Step-by-step explanation:
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Answer:
Step-by-step explanation:
The given data is 11, 77, 35, 5, 76, 34, 89, 92, 22
The total number of items in the data is 9. The width of each class interval would be gotten by dividing the difference between the minimum and maximum items in the data by the number of class intervals. From the information given,
Minimum item = 5
Maximum item = 92
Difference = 92 - 5 = 7
Class width = 87/10 = 8.7
By approximation, it is closest to 10
Therefore, the appropriate class group is 0 to 10
Answer:
x=y/5+6/5
Step-by-step explanation:
Add 6 to both sides of the equation.
5
x
=
y
+
6
Divide each term by 5 and simplify.
x
=
y
/5
+
6
/5
