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trasher [3.6K]
2 years ago
13

A painting has an area of 108 square inches. The dimensions of the painting are 12 and x + 3. What is the perimeter of the paint

ing? Please help ill give you brainlys
Mathematics
2 answers:
slega [8]2 years ago
7 0

Answer:

108 divide 12 and i got 9

then i did 9-3 and i got 6.

12+12+9+9=42

So the perimeter is 42

Welp i don't know if it is correct or not

Step-by-step explanation:

photoshop1234 [79]2 years ago
4 0

Answer:

42 inches

Step-by-step explanation:

x=6

108/12=9

9-3=6

the length of the picture is 12 and the width is 9

12+12+9+9==42

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I think it's 12.50

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4. The side lengths of a square are each 5p. By adding 1 to the length and subtracting 1 from the width, a rectangle is made. Wh
Vilka [71]

Answer:

D. 25p² - 1

Step-by-step explanation:

Each side length of a square = 5p

Length of rectangle = 5p + 1

Width of the rectangle = 5p - 1

Area of rectangle = Length × Width

Area of rectangle = (5p + 1)(5p - 1)

= 5p(5p - 1) +1(5p - 1) (distributive property)

= 25p² - 5p + 5p - 1

Area = 25p² - 1

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2 years ago
Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro
tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation  

n=2700 represent the random sample taken    

X represent the people in England who are deficient in Vitamin D

\hat p=0.2 estimated proportion of England people who are deficient in Vitamin D

\alpha=0.02 represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)    

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.33

And replacing into the confidence interval formula we got:

0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182

0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

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Question 2 of 10
UNO [17]

Answer:

9800000

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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123.85 + 6.19 + 22.29 = $152.33

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