If you do in fact mean
(as opposed to one of these being the derivative of
at some point), then integrating twice gives



From the initial conditions, we find


Eliminating
, we get


![C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)](https://tex.z-dn.net/?f=C_1%20%3D%20-%5Cdfrac%7B%5Cln%286%29%7D5%20%3D%20-%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%20%5Cimplies%20C_2%20%3D%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29)
Then
![\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}](https://tex.z-dn.net/?f=%5Cboxed%7Bf%28x%29%20%3D%20%5Cln%7Cx%7C%20-%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%5C%2Cx%20%2B%20%5Cln%5Cleft%28%5Csqrt%5B5%5D%7B6%7D%5Cright%29%7D)
Answer:

Step-by-step explanation:
(x – 5)^2 + 3(x – 5) + 9 = 0
This is a quadratic equation in x - 5.
Let u = x - 5, then the quadratic equation becomes:
u^2 + 3u + 9 = 0
We can use the quadratic formula to solve for u.





Since u = x - 5, now we substitute x - 5 for u and solve for x.




Answer:
C
Step-by-step explanation:
I'm pretty sure you would have 412.38 (€) because the equation would be $522 × 0.79.
Answer:
Option B
Step-by-step explanation:
Given that the regression equation using least squares for test scores and student teacher ratio is
Test Score = 557.8 + 36.42 In (Income).
Say if 1% income is increased.
Let income be 100
New income = 101
Then we have
Test score original =

Test score new income
= 
Increase = 0.362~0.36
Option B is right.