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sammy [17]
3 years ago
13

Two vertices of a rectangle are (−10, −7) and (−10, 18) .

Mathematics
2 answers:
Bingel [31]3 years ago
8 0

Answer:

The length of the side of the rectangle is 11 units.

Juliette [100K]3 years ago
4 0

Answer:

11 units

Step-by-step explanation:

did the unit test in K12

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Convert y+1=3/4(x-16) to standard form.
Lelu [443]
Standard form: Ax + by =C
so
y+ 1 = 3/4(x - 16)

4(y + 1) = 3(x - 16)
4y + 4 = 3x - 48
3x - 4y = 52

Answer is D. last option
3x - 4y = 52
3 0
3 years ago
Select the correct answer.
sladkih [1.3K]

Answer:

A

Step-by-step explanation:

Because this ia so simple I don't even need to explain to waste my last few brain cells.

8 0
3 years ago
Read 2 more answers
The accompanying data came from a study of collusion in bidding within the construction industry. No. Bidders No. Contracts 2 6
viktelen [127]

Answer:

a)

The proportion of contracts involved at most five bidders is 0.667.

The proportion of contracts involved at least five bidders is 0.51.

b)

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5.

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

Step-by-step explanation:

No. bidders    No. contracts     Relative frequency of contracts

2                         6                       6/102=0.0588

3                         20                     20/102=0.1961

4                         24                     24/102=0.2353

5                         18                       18/102=0.1765

6                         13                        13/102=0.1275

7                          7                          7/102=0.0686

8                          5                          5/102=0.049

9                          6                          6/102=0.0588

10                         2                           2/102=0.0196

11                          1                            1/102=0.0098

Total                  102

a)

We have to find proportion of contracts involved at most five bidders.

Proportion of at most 5= Relative frequency 2+ Relative frequency 3+ Relative frequency 4+ Relative frequency 5

Proportion of at most 5=0.0588+ 0.1961+0.2353+0.1765

Proportion of at most 5=0.6667

The proportion of contracts involved at most five bidders is 0.667.

proportion of at least five bidders= proportion≥5= 1- proportion less than 5

Proportion less than 5=0.0588+ 0.1961+0.2353=0.4902

proportion of at least five bidders=1-0.4902=0.5098

The proportion of contracts involved at least five bidders is 0.51

b)

We have to find proportion of contracts involved  between five and 10 inclusive bidders.

Proportion of contracts between five and 10 inclusive= Relative frequency 5+ Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9+ Relative frequency 10

Proportion of between five and 10 inclusive=0.1765 +0.1275 +0.0686 +0.049 +0.0588 +0.0196

Proportion of between five and 10 inclusive=0.5

The  proportion of contracts involved  between five and 10 inclusive bidders is 0.5

We have to find proportion of contracts involved  strictly between five and 10 bidders.

Proportion of contracts strictly between five and 10=  Relative frequency 6+ Relative frequency 7+ Relative frequency 8+ Relative frequency 9

Proportion of strictly between five and 10=0.1275 +0.0686 +0.049 +0.0588

Proportion of strictly between five and 10=0.3039

The  proportion of contracts involved  strictly between five and 10 bidders is 0.304.

8 0
3 years ago
Find a number that is between 2/7 and 4/11 .
Furkat [3]
To answer this problem, one way is to use the calculator and add directly the two numbers and get the average between the two. The answer is 25/77. We can also get this number by getting the LCM of the denominators which is 77. 2/7 is equal to 22/77 while 4/11 is equal to 28/77. 0.5*(22 +28) is equal to 25. Hence the answer is 25/77. 
7 0
3 years ago
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