okay lets foces on question 20. 3/20
all you need to do is times the dinominator into 100 so 20x5=100 and now you have to multipy the same number that you multiplyed the first one by so 3x5=15 so the anwer would be 15/100 and to put that in a decimal you need to see the number on top witch is 15 so your real ANWSER IS .15
The first step is to determine the distance between the points, (1,1) and (7,9)
We would find this distance by applying the formula shown below
![\begin{gathered} \text{Distance = }\sqrt[]{(x2-x1)^2+(y2-y1)^2} \\ \text{From the graph, } \\ x1\text{ = 1, y1 = 1} \\ x2\text{ = 7, y2 = 9} \\ \text{Distance = }\sqrt[]{(7-1)^2+(9-1)^2} \\ \text{Distance = }\sqrt[]{6^2+8^2}\text{ = }\sqrt[]{100} \\ \text{Distance = 10} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20%5C%5C%20%5Ctext%7BFrom%20the%20graph%2C%20%7D%20%5C%5C%20x1%5Ctext%7B%20%3D%201%2C%20y1%20%3D%201%7D%20%5C%5C%20x2%5Ctext%7B%20%3D%207%2C%20y2%20%3D%209%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B%287-1%29%5E2%2B%289-1%29%5E2%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%20%7D%5Csqrt%5B%5D%7B6%5E2%2B8%5E2%7D%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20%5Ctext%7BDistance%20%3D%2010%7D%20%5Cend%7Bgathered%7D)
Distance = 10 units
If one unit is 70 meters, then the distance between both entrances is
70 * 10 = 700 meters
Answer:
dogs=32
total animal=80
dogs percent=dogs/total animal×100%=32/80×100%=40%
This question is based on prime factorization method.
As given there are 12 peaches and 18 nectarines
Factors of 12 are : 2,3,4,6 and 12
Factors of 18 are : 2,3,6,9 and 18
As mentioned, fruits are divided into the same number of equal groups, so the groups can be formed as-
1. 6 groups of peaches with 2 in each and 6 groups of nectarines with 3 in each,
2. 3 groups of peaches with 4 in each and 3 groups of nectarines with 6 in each.
3. 2 groups of peaches with 6 in each and 2 groups of nectarines with 9 in each.
