Given:
Circumference of a circle = C
Diameter of a circle = d
To find:
The relationship between the circumference, c, and diameter, d, of any circle.
Solution:
We know that, circumference of a circle is
![C=2\pi r](https://tex.z-dn.net/?f=C%3D2%5Cpi%20r)
It can be written as
![C=(2r)\pi](https://tex.z-dn.net/?f=C%3D%282r%29%5Cpi%20)
![[\because d=2r]](https://tex.z-dn.net/?f=%5B%5Cbecause%20d%3D2r%5D)
On dividing both sides by d, we get
![\dfrac{C}{d}=\pi](https://tex.z-dn.net/?f=%5Cdfrac%7BC%7D%7Bd%7D%3D%5Cpi%20)
Therefore, the correct option is (F).
Answer:
She has 7 $5 dollar bills and 4 $1 dollar bills.
Step-by-step explanation:
& times 5 plus 4.
A ton is equivalent to 1000 pounds so:
the elephant weighs 5000 pounds
5000-570= 4430
The elephants weighs 4430 pounds more.
Answer:
.
Step-by-step explanation:
Please consider the complete question.
A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).
Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.
Now, we will use point-slope form of equation as:
, where,
m = Slope
= Given point on the line.
Upon substituting coordinates of point (11,140) in above formula, we will get:
![y-140=5.5(x-11)](https://tex.z-dn.net/?f=y-140%3D5.5%28x-11%29)
![y-140=5.5x-60.5](https://tex.z-dn.net/?f=y-140%3D5.5x-60.5)
![y-140+140=5.5x-60.5+140](https://tex.z-dn.net/?f=y-140%2B140%3D5.5x-60.5%2B140)
![y=5.5x+79.5](https://tex.z-dn.net/?f=y%3D5.5x%2B79.5)
Therefore, our required function would be
.
First you need to find the volume of the cylinder. Then find the volume of all 4 rubber balls (spheres). Subtract the cylinder's volume by the spheres' volumes.
Volume of cylinder: πr²h
π2.5²(20) = 392.7 cm³
Volume of sphere: 4/3πr³
4/3π2.5³ = 65.45 cm³
392.7 - 65.45 = 327.25
The amount of space in the container unoccupied by the rubber balls is 327 cm³.