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kati45 [8]
2 years ago
14

Graph the line that has a slope of 1/4 and includes the point (0,8)

Mathematics
1 answer:
Alex787 [66]2 years ago
3 0

Step-by-step explanation:

Equation of line:

y = mx + c

where m is the slope

and c is the y-intercept (the value of y when x = 0)

In this case, given the slope = 1/4

and y-intercept is 8 (from the point (0,8))

The equation of the following line is:

y =  \frac{1}{4} x + 8

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24 is 4/5% of what number
docker41 [41]

Answer:

The number is 3000

Step-by-step explanation:

Is means equals

24 = 4/5 % *n

Lets change the percent to a decimal.  To change percent, we move the decimal to places to the left.

4/5= .8

4/5 % = .8%  = .008

24 = .008 *n

Divide  each side by .008

24/.008 = .008n/.008

3000 = n

7 0
3 years ago
What is 17.5 times 2.48 show ur work (like this heres an example)
crimeas [40]
I multiplied 17.5 times 2.48 and got 43.4
3 0
3 years ago
Help answer and EXPLAIN STEP BY STEP
pychu [463]

15. (-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

Step 1: Distribute the subtraction sign to all the numbers in the second set of parentheses...

(-k^{3} -5k^{2} + 1) - (6k^{3}-k^{2} -2)

-k^{3} -5k^{2} +1 - 6k^{3} +k^{2} +2

Step 2: Combine like terms (k^{2}'s go with k^{2}'s)

-k^{3} -5k^{2} + 1 - 6k^{3}+k^{2} +2

-5k^{2} +k^{2}

-4k^{2}

-k^{3} -4k^{2} + 1 - 6k^{3}+2

Step 3: Combine like terms (k^{3}'s go with k^{3}'s)

-k^{3} -4k^{2} + 1 - 6k^{3}+2

-k^{3} + (- 6k^{3})

-7k^{3}

-7k^{3} -4k^{2} + 1 +2

Step 4: Combine like terms (normal numbers go with normal numbers)

-7k^{3} -4k^{2} + 1 +2

1 + 2

3

-7k^{3} -4k^{2} + 3

You were correct!

16. 49m^2 - 84mn + 36n^2

I don't really know how to explain this one but I got: (7m-6n)(7m-6n)

7 0
3 years ago
PLEASE HELP!! MATH QUESTION!! 20 points!!
Naddik [55]
Answers
7, 11 are linear.
9 is a quadratic. y = 2x^2 - 3

Problem 11
First find the slope.  Use the first two points to do that.
y2 = 8
y1 = 6
x2 = - 3
x1 = - 1

<u>Sub and solve</u>
y = (y2 - y1) / (x2 - x1)
y = (8 - 6) / (-3 - - 1)
y = 2/- 2
y = - 1

<u>Step 2</u>
Find the y intercept
So far we have 
y = - x + b
x = 0
y = 5
5 = 0 *-1 + b
b = 5

<u>Answer</u>
 y = -x + 5

Problem 9
is the quadratic.

y = a*x^2 + b
when x = 0
y = - 3
y = ax^2 - 3  Now use any other point to solve for a.

Use (2,5)
5 = a(2)^2 - 3  Add 3 to both sides.
5 + 3 = a*4
8 = 4a    Divide by 4
8/4 = a
2 = a

<u>check</u>
Use (-1,1) to check
y = 2x^2 - 3
y = 2(-1)^2 - 3
y = 2*1 - 3
y = 2 - 3
y = - 1     Which is as it should be.

Problem 7
Is linear. Do the same way as 11. 
The graph is included below.

See if you can get the equation line.

You should get 
y = 2x - 4

6 0
3 years ago
Help pls
sveta [45]

5 year olds and younger, 0c

5years to 12 years, 10c

12 to 18 years, 25c

Adules 35, 35c

C is for the amount of people

7 0
2 years ago
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