Answer:
SEVEN!!!!
Step-by-step explanation:
Here is the expansion of <span>(x + y)n </span><span>for </span><span>n = 0, 1,…, 5</span><span> :</span>
<span>(x + y)0 = 1</span>
<span>(x + y)1 = x + y </span>
<span>(x + y)2 = x 2 +2xy + y 2 </span>
<span>(x + y)3 = x 3 +3x 2 y + 3xy 2 + y 3 </span>
<span>(x + y)4 = x 4 +4x 3 y + 6x 2 y 2 +4xy 3 + y 4 </span>
<span>(x + y)5 = x 5 +5x 4 y + 10x 3 y 2 +10x 2 y 3 +5xy 4 + y 5
</span>
hopefuly this helps you understand
Answer:
2.35 calls
Step-by-step explanation:
The presented scenario can be modeled by a Poisson distribution with an average number of calls (μ) of 5.5 during the noon hour on Mondays.
Therefore, the standard deviation for the number of calls received, X, is given by:
The standard deviation of X is 2.35 calls.
Answer:
11.1
Step-by-step explanation:
0.5(−77.8−11)/−4
=(0.5)(−88.8)/−4
=−44.4/−4
=11.1
Part percent
—— = ————. I use that method a lot and it helped me. ANSWER:65%
Whole 100
