M + 5q; where m=1, and q = 5 I
2 answers:
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Given:
The given sequence is:
To find:
The recursive formula for , the nth term of the sequence.
Solution:
We have,
Here, the first term is 5.
The common difference is -7.
The recursive formula for the nth term of the sequence is
Where, is the common difference.
Putting in the above formula, we get
Therefore, the recursive formula for the nth term of the sequence is .
<h3>Answer: x(x+1)(5x+9) </h3>
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Work Shown:
5x^3 + 14x^2 + 9x
x( 5x^2 + 14x + 9 )
To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.
A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula
Then use those two solutions to find the factorization
x = -1 or x = -9/5
x+1 = 0 or 5x = -9
x+1 = 0 or 5x+9 = 0
(x+1)(5x+9) = 0
So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)
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Overall,
5x^3 + 14x^2 + 9x
factors to
x(x+1)(5x+9)