To solve for
You first need to find a common denominator.
To do so, you need to make both denominators 10 by multiplying the top and bottom of
by 5
=
Reduce by dividing both the top and bottom by 2
Your answer is
Answer:
Option C is correct.
Step-by-step explanation:
We are given the expression:
The value of a =5 and k = -2
Putting the values and solving
Option C is correct.
Answer:
(1, 1), (2, 2.333) and (3, 3.666).
Step-by-step explanation:
So, for x = 1, we have:
4*1 - 3y = 1
3y = 3
y = 1
For x = 2, we have:
4*2 - 3y = 1
3y = 7
y = 2.333
For x = 3, we have:
4*3 - 3y = 1
3y = 11
y = 3.666
The points we need to plot is (1, 1), (2, 2.333) and (3, 3.666).
Answer:
option: B is correct
A reflection across line n followed by a 270° rotation about point P.
Step-by-step explanation:
Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".
Hence, option B is correct.
( A reflection across line n followed by a 270° rotation about point P )
Answer:
Height of the fighter plane =1.5km=1500 m
Speed of the fighter plane, v=720km/h=200 m/s
Let be the angle with the vertical so that the shell hits the plane. The situation is shown in the given figure.
Muzzle velocity of the gun, u=600 m/s
Time taken by the shell to hit the plane =t
Horizontal distance travelled by the shell =u
x
t
Distance travelled by the plane =vt
The shell hits the plane. Hence, these two distances must be equal.
u
x
t=vt
u Sin θ=v
Sin θ=v/u
=200/600=1/3=0.33
θ=Sin
−1
(0.33)=19.50
In order to avoid being hit by the shell, the pilot must fly the plane at an altitude (H) higher than the maximum height achieved by the shell for any angle of launch.
H
max
=u
2
sin
2
(90−θ)/2g=600
2
/(2×10)=16km
