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2 years ago

Dave rented a limousine for his wife's birthday. The hourly rate is $80. They used the limousine for 5 hours, plus Dave gave the

Mathematics

1 answer:

GREYUIT [131]2 years ago

7 0

Answer: $440

Step-by-step explanation:

80*5 = 400

10% of 400 = 40

400 + 40 = 440

Ans. $440

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4(8x−1) = 19+32x

Fantom [35]

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

Answer:

Let's solve your equation step-by-step.

4 ( 8x − 1 ) = 19 + 32x

Step 1: Simplify both sides of the equation.

4 ( 8x − 1 ) = 19 + 32x

( 4 ) ( 8x ) + ( 4 ) ( −1 ) = 19 + 32x ( Distribute )

32x + −4 = 19 + 32x

32x − 4 = 32x + 19

Step 2: Subtract 32x from both sides.

32x − 4 − 32x = 32x + 19 − 32x

−4 = 19

Step 3: Add 4 to both sides.

−4 + 4 = 19 + 4

0 = 23

Answer:

There are no solutions.

<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3

5 0

2 years ago

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Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

7 0

2 years ago

there are 300 student and teachers at a sports event.Grade k to 2 is students: 137 Grade 3 to 5 students: 145 Teachers: ? what i

AVprozaik [17]

Answer:

Percentage of teachers = 6%

Step-by-step explanation:

Given;

Number of grade k-2 students = 137

Number of grade 3-5 students = 145

Total = 300

Number of teachers = 300 - (137+145) = 18

Percentage of teachers = (number of teachers÷total)× 100%

%T = (18/300) × 100

%T = 6%

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2 years ago

What is the distance between the points (5, 1) and (-3,-5)?

Reil [10]

Answer: THIRD OPTION.

Step-by-step explanation:

For this exercise you need to use the formula for calculate the distance between two points. This is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the following points:

$(5, 1)$ and $(-3,-5)$

You can identify that:

$x_2=-3\\x_1=5\\\\y_2=-5\\y_1=1$

Knowing these values, the next step is to substitute them into the equation for calculate the distance between two points and then evaluate.

Therefore, the distance between $(5, 1)$ and $(-3,-5)$ is:

$d=\sqrt{(-3-5)^2+(-5-1)^2}\\\\d=10$

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2 years ago

Hey can somebody help y+5=2(x+1)

kifflom [539]

If you're looking for the equation, the answer is y=2x-3

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2 years ago

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