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3 years ago

What is the degree of angle YQR

Mathematics

1 answer:

katovenus [111]3 years ago

4 0

Answer: Angle is 3

Step-by-step explanation:

16x - 27 = 5x + 6

-5x -5x

______________

11x - 27 = 6

+ 27 +27

___________

11x = 33

__ __

11 11

x = 3

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3x-1/5=x+1/3 solve for x

Maru [420]

Answer:

x = 2

Step-by-step explanation:

First, you cross multiply then that will give you

9x - 3 = 5x + 5

collect like terms

9x - 5x = +5 + 3

= 4x = 8

Divide both sides by the coefficient of x that's 4

= 2

6 0

2 years ago

Find (a) the slope of the curve at the given point P, and (b) an equation of the tangent line at P: y = 9x^2 + 5 ; P (2,41)

Flauer [41]

Answer:

(a) 36

(b) y = 36x-31

Step-by-step explanation:

(a) dy/dx = 18x

slope of tangent at (2, 41) = 18(2)

= 36

(b) using y-y1 = m(x-x1)

y-41 = 36(x-2)

y = 36x-31

6 0

3 years ago

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

What is an equation in point-slope form the line that passes through the point (-3,5) and (2,-3)?

lyudmila [28]

Answer:

Y-5=-8/5 (x+3)

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Solve the following factorize and the en- equation of quadrate equation X² + 5x + 7 x = 0

nlexa [21]

Answer:

{-12,0}

Step-by-step explanation:

first to solve this can collect like terms and add

X² +12x=0

and solve it by factorization method

X² +12x=0

x(x+12)=0

it means x multiplied by x = X² then x multiplied by 12 = 12x

so this means x or (x+12) equals to zero

x=0 and (x+12)=0

x+12=0

x=-12

so the solution set is {-12,0}

but can also be done by formula method

8 0

2 years ago

What is the degree of angle YQR​

What is the degree of angle YQR