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3 years ago

The info is in the picture

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

Answer:

no it isn't the inverse.

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5(2x)to the third power

kumpel [21]

(5(2x))^3
Use the property of exponents:
(5^3)*(2x)^3
Simplify the exponents:
125*8*x^3
Simplify the numbers and multiply the integers:
1000*x^3

Hope this helps :)

5 0

3 years ago

Help me please 10 points I’m only in 8th

AnnyKZ [126]

The answer is

5.09902

5 0

3 years ago

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∠ABD is formed by a tangent and a secant intersecting outside of a circle. If minor arc AC = 72° and minor arc CD = 132°, what i

notsponge [240]

you're given both arcs, minor and major, or near and far arcs, all you need to do, is really plug them in

3 0

3 years ago

#6 from the paper please

BabaBlast [244]

Answer:

EK = 9

Step-by-step explanation:

x + 11 = -5 + 2x -5 + 2x

x+11 = -10 + 4x

11 = 3x - 10

3x = 21

x = 7

EK =-5 + 2 × 7

EK = 14 - 5

EK = 9

6 0

3 years ago

Read 2 more answers

Which of the following illustrates a phase shift?

Natasha_Volkova [10]

Answer:

A. y = -2 - cos(x-π)

Explanation:

The general form of the trig equation is:

y = A sin (Bx + C) + D

where:

A is the amplitude

$\frac{2\pi}{B}$ is the period

$\frac{-C}{B}$ is the phase shift

D is the vertical shift

Now, let's check the choices:

A. y = -2 - cos(x-π)

$\frac{-C}{B} = \frac{\pi}{1} = \pi$

Therefore, the function has a phase shift of π

B. y = 3 cos(4x)

$\frac{-C}{B} = \frac{0}{4} = 0$

Therefore, the function has no phase shift

C. y = tan(2x)

$\frac{-C}{B} = \frac{0}{2} = 0$

Therefore, the function has no phase shift

D. y = 1 + sin(x)

$\frac{-C}{B} = \frac{0}{1} = 0$

Therefore, the function has no phase shift

Based on the above, the correct answer is A

Hope this helps :)

3 0

3 years ago

Read 2 more answers