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2 years ago

create a story problem about a fish tank for the tape diagram below. Your story must include a fraction.

Mathematics

1 answer:

sladkih [1.3K]2 years ago

8 0

Answer:

Step-by-step explanation:

A large aquarium has a length of 84 inches. It is located in a large basement that is properly heated and ventilated. The width should be close to 1/2 the length and the height ought to be 1/6 the length. If the fish tank requires that an aerator be placed every 28 inches along the back edge, how many aerators are needed. Note: an aerator is not placed in either corner.

Width =_________________

Height= ________________

Aerators = ______________

Find the number of cubic inches of the fish tank. If an aerator will provide enough oxygen to aerate 5 cubic feet,, do you have enough aerators for the fish to live comfortably? If the answer is no, then how many aerators do you need?

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A sample of 5 buttons is randomly selected and the following diameters are measured in inches. Give a point estimate for the pop

Helen [10]

Answer:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

Step-by-step explanation:

For this case we have the following data:

1.04,1.00,1.13,1.08,1.11

And in order to estimate the population variance we can use the sample variance formula:

$s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

But we need to calculate the mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_I}{n}$

And replacing we got:

$\bar X = \frac{ 1.04+1.00+1.13+1.08+1.11}{5}= 1.072$

And for the sample variance we have:

$s^2 = \frac{(1.04-1.072)^2 +(1.00-1.072)^2 +(1.13-1.072)^2 +(1.08-1.072)^2 +(1.11-1.072)^2}{5-1}= 0.00277\ approx 0.003$

And thi is the best estimator for the population variance since is an unbiased estimator od the population variance $\sigma^2$

$E(s^2) = \sigma^2$

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3 years ago

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lana66690 [7]

Answer:

Can I get more details on this question?

Step-by-step explanation:

If so, I can probably help you a little bit more. And I will edit my response

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2 years ago

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Explanation:
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2 years ago

create a story problem about a fish tank for the tape diagram below. Your story must include a fraction.​

create a story problem about a fish tank for the tape diagram below. Your story must include a fraction.