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Alinara [238K]
2 years ago
5

5. Find x and UV if V is between U and w, with UV = 3x + 7, VW = 4x + 5 and UW = x + 96

Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0
X=626 and I 7278 baby +_
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Pls pls help I’m really confused could someone explain to me pls
kenny6666 [7]
Answer: 11.6

--------------------------------------

Explanation:

See the attached image for a visual reference

The distance from point D to E is 21 units. Point C is the midpoint, so CD is 10.5 units long (21/2 = 10.5)

We have a right triangle ACD. The legs are
AC = 5
CD = 10.5
The hypotenuse is 
AD = x
Because AD is another radius of the same circle

Use the pythagorean theorem to find x
a^2 + b^2 = c^2
5^2 + 10.5^2 = x^2
25 + 110.25 = x^2
135.25 = x^2
x^2 = 135.25
x = sqrt(135.25)
x = 11.629703349613
which rounds to 11.6 when rounding to the nearest tenth (one decimal place)

3 0
3 years ago
1. Tamara draws a tile from a bag and records the results. The bag contains tiles labeled, WATER, M, EL. O, and N. Based on this
Katen [24]

Answer:

u think b

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Find an equation, or a set of equations, to describe the set of points that are equidistant from the points p(−9, 0, 0) and q(3,
wariber [46]
X = -3.  
The distance from p(-9, 0, 0) is
 d = sqrt((x+9)^2 + y^2 + z^2) 
 The distance from q(3,0,0) is
 d = sqrt((x-3)^2 + y^2 + z^2) 
 Let's set them equal to each other.
 sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
  Square both sides, then simplify
 (x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
 x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
 18x + 81 = - 6x + 9
 24x + 81 = 9
 24x = -72
 x = -3 
 So the desired equation is x = -3 which defines a plane.
7 0
3 years ago
The fair spinner shown in the diagram above is spun work out the probability of getting a factor of 8​
sashaice [31]

Answer:1/8

Step-by-step explanation:cuz

3 0
3 years ago
Please help me solve---- -20-(4x-1)=-15
nikklg [1K]
I hope this helps you -20-(4x-1)=-15 -20-4x+1=-15 -20+1+15=4x -4=4x x=-1
7 0
3 years ago
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