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2 years ago

Solve 2x = -16 a.-8 b.8 c.1/8 d.-1/8

Mathematics

1 answer:

harina [27]2 years ago

4 0

Answer:

Step-by-step explanation:

The correct answer will be A

Have a great day

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Please come answer ASAP!!! 5 - n divided by 3 = 4 what is the value of n?

Varvara68 [4.7K]

Hey there!

The equation we have been given is 5 - n/3 = -4.

Let's start by subtracting 5 from each side.

-n/3 = -9

Multiply each side by 3.

-n = -27

Multiply each side by -1.

n = 27

Check our answer.

5 - 27/3 = -4

5 - 9 = -4

-4 = -4

The value of n is 27.

Hope this helps!

7 0

3 years ago

Please solve this quickly

adell [148]

Answer:

I Didn't see nothing

Step-by-step explanation:

So I can't help you

7 0

2 years ago

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The ratio of adults to students on the field trip is 3 to 5. If there are 15 students on the field trip, how many adults are the

Kazeer [188]

Answer:

There are 9 adults

Step-by-step explanation:

3:5 = x:15

3/5 = x/15

3(15) = 5x

5x = 45

x = 9 adults

3:5 = 9:15

4 0

3 years ago

The Brown family bought 9 bags of cookies. Each bag had 16 cookies. They have since eaten 26 of the cookies. How many cookies do

grigory [225]

Answer:

118 cookies

Step-by-step explanation:

1. 9x 16

2.144-26

And then get 118! Have a nice day YW!!!!!???

3 0

2 years ago

A cyclist travels at distance of 400 meters in 120 seconds towards school, calculate his speed. (Show your work)

DochEvi [55]

we know that

The scalar magnitude of the velocity vector is the speed. The speed is equal to

$Speed=\frac{distance}{time}$

in this problem we have

$distance=400\ m \\time=120\ sec$

substitute in the formula

$Speed=\frac{400}{120}$

$Speed=3.5\frac{m}{sec}$

therefore

the answer Part a) is

the speed is equal to $3.5\frac{m}{sec}$

Part b) Find the velocity

we know that

Velocity is a vector quantity; both magnitude and direction are needed to define it

in this problem we have

the magnitude is equal to the speed

$magnitude=3.5\frac{m}{sec}$

$direction=North\ East\ (NE)$

therefore

the answer Part b) is

the velocity is $3.5\frac{m}{sec}\ North\ East\ (NE)$

Part c)

we know that

the acceleration is equal to the formula

$a=\frac{V2-V1}{t2-t1}$

in this problem we have

$V2=0 \\V1=3.5\frac{m}{sec}$

$t2=15\ sec\\t1=0$

substitute in the formula

$a=\frac{0-3.5}{15-0}$

$a=-\frac{3.5}{15}\frac{m}{sec^{2}}$

$a=-\frac{7}{30}\frac{m}{sec^{2}}$

therefore

the answer Part c) is

the acceleration is $-\frac{7}{30}\frac{m}{sec^{2}}$

This is an example of negative acceleration

7 0

3 years ago

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