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tiny-mole [99]
3 years ago
11

What would the class size be if 30 people represent 40% of the class?

Mathematics
1 answer:
anastassius [24]3 years ago
6 0

Answer:

110 students

Step-by-step explanation:

%40 Divide 30

30 divided by %40 is 0.75

SO there is 60% left

%60 divided by 0.75

That is 80

80 + 30 =

110

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Jeff answered all 25 questions on his chemistry test. For each right answer, he got 4 points and for each wrong answer he lost 2
timurjin [86]

Answer:

Jeff got 20 answers right.

Step-by-step explanation:

The maximum number of points Jeff can get is 100. (25 * 4) However, for each question he gets wrong, he's actually losing 6 points because he doesn't get the four points for getting right, and has the additional -2 points for getting it wrong. Since he only got a score of 70, that means he lost 30 points.

30/6 = 5. So he missed 5 question and got 20 question right.


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There should be 30 cars in the parking lot
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What is the y intercept of f(x)=2x^2+8x+6
xxMikexx [17]

Answer:

6 is the y intercept

Step-by-step explanation:

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3 years ago
What is the answer to 227-198
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The answer to the problem is 29
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3 years ago
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How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the populati
marshall27 [118]

Using the z-distribution, it is found that a sample of 171 should be selected.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For this problem, the parameters are:

z = 1.96, \sigma = 40, M = 6

Hence we solve for n to find the needed sample size.

M = z\frac{\sigma}{\sqrt{n}}

6 = 1.96\frac{40}{\sqrt{n}}

6\sqrt{n} = 40 \times 1.96

\sqrt{n} = \frac{40 \times 1.96}{6}

(\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2

n = 170.7.

Rounding up, a sample of 171 should be selected.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
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