Answer:
the rate of change of the volume of the cube is -9747 cubic millimeters per minute
Explanation:
The computation of the rate of change of the volume of the cube is given below:
As we know that
The volume of the cube is x^3
Now differentiate it with time t
So
dV÷ dt = 3x^2 dx ÷ dt
Now put the values
= 3(19)^2 (-9)
= -9747 cubic millimeters per minute
hence, the rate of change of the volume of the cube is -9747 cubic millimeters per minute
