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ivann1987 [24]
3 years ago
5

(-8, -1) slope = -3/4

Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

y=-3/4x - 7

Step-by-step explanation:

When finding the slope given a point and a slope, we do the following.

y=mx+b  (Slope-intercept Form)

m is the slope and x,y are the points

Plug in everything

-1= -3/4(-8)+b

Multiply

-1 = 6 + b

-7 = b

This gives us the final equation of y=-3/4x - 7

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What is the value of the expression 18-2×(4+3)
Vika [28.1K]
The value would be 4.

First, you have to do 4 + 3 because it's in parenteces. This equals 7
Secondly, you have to do 2 x 7, which is 14.
Last you have to do 18 - 14 which is 4.
3 0
3 years ago
Read 2 more answers
If r(X)=2-x^2 and w(X)=X-2, what is the range of (w*r)(X)
slega [8]
The given function are
r(x) = 2 - x²    and     w(x) = x - 2
<span>(w*r)(x) can be obtained by multiplying the both function together
</span>
So, <span>(w*r)(x) = w(x) * r(x) = (x-2)*(2-x²)</span>
<span>(w*r)(x) = x (2-x²) - 2(2-x²)</span>
            = 2x - x³ - 4 + 2x²

∴ <span>(w*r)(x) = -x³ + 2x² + 2x - 4
</span>

<span>It is a polynomial function with a domain equal to R
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The range of <span>(w*r)(x) can be obtained by graphing the function
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To graph (w*r)(x), we need to make a table between x and (w*r)(x)

See the attached figure which represents the table and the graph of <span>(w*r)(x)
</span>

As shown in the graph the range of <span>(w*r)(x) is (-∞,∞)
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8 0
3 years ago
Read 2 more answers
5t^2 - 5.5 - 3.5t + 1.5t^2 +4t
RideAnS [48]
The answer is 6.5t2+0.5t−5.5 , it’s simplified
8 0
3 years ago
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How can i find the midpoint of a line segment ?​
eimsori [14]

Answer:

add both x coordinates and divide them by 2.

add both y coordinates and divide them by 2.

Now final product should be (x,y)

Step-by-step explanation:

Example.

let's take 2 points:

(2,5) and (7, 9)

let's add both x coordinates.

2+7 = 9

now add both y coordinates.

5+9 = 14

Now divide both by 2.

Final answer should be (4.5, 7) = this is your midpoint

8 0
3 years ago
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

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Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

\sqrt{n} = \frac{1.2996}{0.07}

\sqrt{n} = 18.5658

(\sqrt{n})^{2} = (18.5658)^{2}

n = 345

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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