What is the absolute value of the complex number -4-sr2i

1 answer:

8 0

The complex number seems to be -4 - (√2) i

The absolute value of a complex number a + bi is defined as

|a + bi| = √ [(a^2) + (b^2)].

So, the absolute value of - 4 - (√2)i is

| -4 - (√2)i | = √ [ (4)^2 + (√2)^2 ] = √ [ 16 + 2 ] = √18 = √(9*2) = √9 * √2 = 3√2

Answer: 3√2

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