Please help on part B

A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessi

Elza [17]

Question:

A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.

What is the number of seats occupied by concessionary ticket holders?.

Answer:

60 seats

Step-by-step explanation:

Given

Number of seats = 270

Occupied Seats = 5/9

Concessionary ticket holders = 40% of occupied Seats

Required

The number of seats occupied by concessionary ticket holders

First the number of occupied seat has to be calculated.

$Occupied\ Seats = \frac{5}{9} * 270$

$Occupied\ Seats = \frac{1350}{9}$

$Occupied\ Seats = 150$

Next is to determine the number of seats occupied by concessionary ticket holders.

$Number = 40\%\ of\ occupied\ seats$

$Number = 40\%\ of\ 150$

Convert percentage to decimal

$Number = 0.4 * 150$

$Number = 60$

<em>Hence, 60 seats were occupied by concessionary ticket holders.</em>

5 0

3 years ago

Haley bought 3 notebooks that each cost the same amount and 1 backpack that cost $36. The items she bought cost a total of $48 b

mel-nik [20]

The answer is 4$ per note book

5 0

3 years ago

Read 2 more answers

A simplifie 6 × ( - 24 ) ÷ ( -4 )

kumpel [21]

$\huge\textbf{Hey there!}$

$\huge\boxed{\mathsf{6\times(-24)\div (-4)}}\\\huge\boxed{= \mathsf{\dfrac{6(-24)}{-4}}}\\\huge\boxed{\mathsf{= \dfrac{\bold{-144}}{-4}}}\\\huge\boxed{\mathsf{\dfrac{-144\div-4}{-4\div-4}}}\\\huge\boxed{= \mathsf{\dfrac{\bold{36}}{1}}}\\\huge\boxed{\mathsf{= 36\div1}}\\\huge\boxed{\mathsf{= 36}}\\\\\\\huge\text{\bf Therefore, your answer is: \boxed{\mathsf{36}}}\huge\checkmark$

$\huge\text{\bf Good luck on your assignment and enjoy}\\\huge\text{\bf your day!}$

~ $\frak{Amphitrite1040:)}$

8 0

3 years ago

La dirección del Colegio Montes y los padres de familia están organizando un viaje cultural a Guanajuato para los alumnos de seg

notsponge [240]

Answer:

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the simultaneous equation,

The hotel has 15 single rooms and 32 double rooms.

Step-by-step explanation:

English Translation

The management of Colegio Montes and the parents are organizing a cultural trip to Guanajuato for second grade students and their teachers. Students will sleep in double rooms and teachers in singles. The hotel has double rooms (2 beds) and single rooms (1 bed), totaling 47 rooms and 79 beds. To confirm if they can be accommodated, they want to know how many rooms there are of each type. If "x" denotes single rooms and "y" denotes double rooms, Write the system of equations that represents the situation: Equation that represents the number of rooms (1) Equation that represents the number of beds (2)

Solution

The number of single rooms = x

The number of double rooms = y

The number of beds in single rooms = x

The number of beds in double rooms = 2y

Total number of rooms = 47

Total number of beds = 79

Sum of single and double rooms = Total number of rooms

x + y = 47 (eqn 1)

Sum of the beds in the single rooms and the beds in the double rooms = Total number of beds

x + 2y = 79 (eqn 2)

Writing the equations together

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the equations simultaneously,

x = 15, y = 32

Hence, the hotel has 15 single rooms and 32 double rooms.

Hope this Helps!!!

6 0

3 years ago

If θ=0rad at t=0s, what is the blade's angular position at t=20s

babunello [35]

The attached figure represents the relation between ω (rpm) and t (seconds)
To find the blade's angular position in radians ⇒ ω will be converted from (rpm) to (rad/s)
              ω = 250 (rpm) = 250 * (2π/60) = (25/3)π    rad/s
              ω = 100 (rpm) = 100 * (2π/60) = (10/3)π    rad/s

and from the figure it is clear that the operation is at constant speed but with variable levels
            ⇒   ω = dθ/dt   ⇒   dθ = ω dt

            ∴    θ = ∫₀²⁰ ω dt

while ω is not fixed from (t = 0) to (t =20)
the integral will divided to 3 integrals as follow;
       ω = 0                                          from t = 0 to t = 5
       ω = 250 (rpm) = (25/3)π            from t = 5   to t = 15
       ω = 100 (rpm) = (10/3)π            from t = 15 to t = 20

∴ θ = ∫₀⁵ (0) dt   + ∫₅¹⁵ (25/3)π dt + ∫₁₅²⁰ (10/3)π dt

the first integral = 0
the second integral = (25/3)π t = (25/3)π (15-5) = (250/3)π
the third integral = (10/3)π t = (25/3)π (20-15) = (50/3)π

∴ θ = 0 + (250/3)π + (50/3)π = 100 π

while the complete revolution = 2π
so instantaneously at t = 20
∴ θ = 100 π - 50 * 2 π = 0 rad

Which mean:
the blade will be at zero position making no of revolution = (100π)/(2π) = 50

3 0

4 years ago

Please help on part B​

Please help on part B