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NemiM [27]
3 years ago
13

Put these in order starting from the smallest 6^2 3^4 2^9 5^3

Mathematics
1 answer:
Levart [38]3 years ago
4 0

Answer:

6^2, 3^4, 5^3, and 2^9

Step-by-step explanation:

6^2= 36

3^4= 81

5^3= 125

2^9= 512

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What are three powers that have values greater than 500 and less than 550
igomit [66]

Solution:

The three powers whose value is greater than 500 and less than 550 can be find by following procedure.

We will solve this problem by Hit and trial method by finding the squares, cubes, fourth power, Fifth Power,...etc. of different natural numbers.

23²= 529

8³ = 8 × 8 × 8 =512

2^8=512

The three powers are →→→Eighth power of 2, Square of 23, and Cube of 8.

8 0
3 years ago
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Help, please the question and thank you
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Answer:

The scale factor is 1.5.

Step-by-step explanation:

Divide the length of the image, 12, by the length of the preimage, 8, which will give you 1.5

12 ÷ 8 = 1.5

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2 years ago
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jek_recluse [69]
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4 0
3 years ago
Solve 9x + 3 = -33 . PLEASE HELP ME IT WILL MAKE MY DAY​
ValentinkaMS [17]

:  \implies \sf 9x + 3 =  - 33

: \implies \sf 9x =  - 33 - 3

:  \implies \sf 9x =  - 36

:  \implies \sf x =  \dfrac{ - 36}{9}  =  - 4

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NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?
qwelly [4]

Answer:

Vertex is (-8, 4)  not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4

Complete the square by squaring half the coefficient of <em>x </em>and adding it in the space.

(\frac{16}{2})^2=64

Add 64 in the space you made, then compensate for that at the end of the expression by <u>subtracting</u>  -\frac{1}{8}(64)=-8

y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4

The x-coordinate of the vertex is the <u>opposite</u> of +8, the number inside the parentheses.  The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

8 0
3 years ago
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